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JulijaS [17]
2 years ago
9

Find the average rate of change of the quadratic function

x)" alt="f(x)" align="absmiddle" class="latex-formula"> over the interval -2 \leq x \leq 3. Use the following table, which shows the values of the function for various values of x.
a. 7
b. -7
c. 5
d. -5

Mathematics
1 answer:
Gala2k [10]2 years ago
6 0
The answer to the question is B -7
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57.6² = 33.8² + QR²
QR² = 2.175,32
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57.6/sen90º = 46.64/sen(P)
sen(P) = 46.64*sen90º/57.6
sen(P) = 0.809
angle P is sen^-1 = 54.06º ≈ 54.1º

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3 years ago
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Function p(x), shown below, is translated 10 units up to create function q(x).
natulia [17]

Answer: q(x) = 0.005(x - 40)² + 70

<u>Step-by-step explanation:</u>

f(x) = a(x - h)² + k   <em>where a is the vertical stretch and (h, k) is the vertex.</em>

Which coordinate shifts the graph up?<em> The y-coordinate for the vertex is k.</em>

p(x) = 0.005(x - 40)² + 60

q(x) = 0.005(x - 40)² + 60 <u>+ 10</u>

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3 years ago
BRAINLIEST!!! Plz help ASAP
Svetllana [295]

Answer: R = (4, 5)

Step-by-step explanation: Midpoint is simply the center of a line. So, the equation for it is ((x1+x2)/2, (y1+y2)/2). Hence for this,

x coordinate- (6+x)/2=5

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y coordinates- (9+y)/2=7

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3 years ago
Find the percent increase. Round to the nearest percent. From 85 books to 143 books The percent increase is​
klasskru [66]

We are given :

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Let's find the percent increase with the help of formula:

\boxed{ \sf \: formula : 100 \times  \frac{(final - initial)}{initial} }

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

\tt \% \: increase =  100 \times \frac{(143 - 85)}{85}

\tt  \% \: increase = 100 \times  \frac{58}{85}

\tt\% \: increase = 20 \times   \frac{58}{17}

\tt\% \: increase =  \frac{1160}{17}

\tt\% \:increase = 6823.53

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