Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28
Answer: 28
The correct answer is = because 4/6 simplifies to 2/3
Answer:
x^2(3x-2) cubic inches OR in^3
OR
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3
I AM UNAWARE IF YOU ASKED THAT ONE SIDE IS (3X-2) OR ALL. I WILL ANSWER BOTH PARTS
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<em>NOTE</em><em>:</em><em> </em><em>'</em><em>^</em><em>'</em><em> </em><em>MEANS</em><em> </em><em>TO</em><em> </em><em>THE</em><em> </em><em>POWER</em><em> </em><em>OF</em><em>.</em><em>.</em>
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Volume = v, abc = 3 sides of cube (height, width, length)
Using the formula for volume in a cube,

We can solve this.
If one side is (3x-2)in,
- (3x-2)(x)(x) = v.... x are the other two sides
- x^2(3x-2) = v
x^2(3x-2) cubic inches OR in^3
If all sides are (3x-2)in,
Use the formula,

We can solve this.
- (3x-2)(3x-2)(3x-2) = v
- (3x-2)^3 = v.... 3x = a and -2 = b
- (3x)^3 + [(3)(3x)(2)][2-3x] - (2)^3 = v
- 27x^3 + 18x(2-3x) -8 = v
- (27x^3 + 36x - 54x^2) - 8 = v.. Terms inside brackets - take 3x as common and leave out 8
- 3x(9x^2 -18x +12) = v... Take 3 as common again in the brackets
- 3x [ 3 ([3x^2 -6x] + 4) -8 = v....Take 3x common in the terms in square brackets
- 3x [ 3 [ 3x (x-2) + 4 ]] - 8 = v
- 3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 = v
3x { 3 [ 3x ( x - 2 ) + 4 ] } - 8 cubic inches OR in^3
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If you have any questions regarding formulas or anything, comment and I will get back to you asap.
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Answer: r_max = 1.75m
Step-by-step explanation:
Below is a rather brief analysis to solving this problem.
The phone starts sliding when along incline,
when F_net = m g sin(theta) - fs_max = 0
and fs_max = us N = us m g cos(theta)
m g sin(theta) - us m g cos(theta) =
us = tan(theta) = tan38 = 0.781
On merry - go - round,
fs_max = us N = us m g
Using F = m a
fs_max = m w^2 r_max and w = 2pi / T
us m g = m (2 pi / T)^2 (r_max)
0.781 x 9.81 = (2 pi / 3)^2 (r_max)
r_max = 1.75 m
cheers i hope this helped !!