Answer:
SOLVE FOR RECTANGLE
Area: lw (length times width)
rectangle: lw (6x6)
AREA=36in
SOLVE FOR TRIANGLE B
Area: A=hbxb/2
A=hb/b2=6·6/2=18
TRIANGLE B=18in
SOLVE FOR TRIANGLE A
Area: A=hbxb/2
The height looks half the height as the other triangle
A=hb/b2=3·4/2=6
TRIANGLE A=6in
{ADD}
36+18+6
TOTAL: 60in
Step-by-step explanation:
HOPE THAT HELPED!!!
For this case, the first thing we must do is define variables:
x = number of quarters
y = number of dimes
We now write the system of equations:
x + y = 28
0.25x + 0.10y = 4.05
Solving the system of equations we have:
x = 8.33
y = 19.66
Rounding:
x = 8
y = 20
Answer:
the college student has:
8 quarters
20 dimes
Answer:
3/7 or 3 to 7 both are the same ratio.
Step-by-step explanation: