Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
The answer to your question would be 0.01
Answer:
The slope is -3/4
Step-by-step explanation:
We need two points to find the slope
We have one point at (0,5) and we have one point at (4,2)
We can use the slope formula
m = (y2-y2)/(x2-x1)
= (2-5)/( 4-0)
= -3/4
The slope is -3/4
<span>Yes, it is a parallelogram because the slope of segment AB equals the slope of segment DC, which equals negative start fraction four over three end fraction, and AD = BC = 10 units.</span>
Answer:35 square
Step-by-step explanation:
