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4 years ago

Eieven

2 answers:

3 0

I can not see the graph but start the answer by saying “To be proportional the line must start threw the Origin and be linear.” Then say why it why not it is. So if it’s is not say it doesn’t go threw the origin of it is not linear. Does that make sense?? Hope I helped

RoseWind [281]4 years ago

3 0

-20 is the constant of proportionality

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Two sides of a triangle have the same length. The third side measures 7m less than twice the common length. The perimeter of the

Gwar [14]

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Step-by-step explanation:

I am pretty sure your answer is 3

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4 years ago

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Factor out the GCF from the terms of the polynomial 2x3 − 5x2 + 25. A. x2(2x − 5) + 25 B. The polynomial is already fully factor

Reptile [31]

Answer:

Step-by-step explanation:

2x3 − 5x2 + 25

2x³ -5x²+25

2x³ -5(x²-5)

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3 years ago

Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$