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mart [117]
3 years ago
6

Please help its timed thank u

Mathematics
1 answer:
slega [8]3 years ago
7 0

Answer:the third one (c)

Step-by-step explanation:

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-12+x-34=60<br> If you like this question please rate this five stars!<br> Thank you!
natulia [17]

Answer:

x=106

Step-by-step explanation:

Let's solve your equation step-by-step.

−12+x−34=60

Step 1: Simplify both sides of the equation.

−12+x−34=60

−12+x+−34=60

(x)+(−12+−34)=60(Combine Like Terms)

x+−46=60

x−46=60

Step 2: Add 46 to both sides.

x−46+46=60+46

x=106

8 0
3 years ago
in chemistry class Andrew has earned scores of 64 69 and 73 on three tests he must maintain an average of 72
olganol [36]
You haven't told me what the question is.  But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye.  It was quite fuzzy, but I think
the question is

                   "What score does Andrew need on the next test
                     in order to raise his average to 72% ?"

The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck.  So we'll just go ahead
and answer that one.  I hope it's the correct question.

The average score on 4 tests is

                                     (1/4) (the sum of all the scores) .

In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be

                                         (4) x (72%)  =  288% .

Out of that total that he needs, he already has 

                            (64% + 69% + 73%) = 206%

on the first three tests.

So in order to average 72% for all 4 tests,
he'll need to score

                             (288%  -  206%)  =   82%

on the fourth one.
6 0
3 years ago
4. MAIL It cost Ramon $3.73 to mail a package to his grandmother. The post
Alex Ar [27]

Answer:

4 pounds

Step-by-step explanation:

First, I subtracted the cost of the first pound from the final product (3.73 - 2.38) and I got 1.35. I then divided the 1.35 by .45 (the 45 cents) to figure out how many more pounds the package was from the initial 1 pounds. 1.35/.45 is 3, plus the 1 pound from the beginning makes 4 pounds in total.

6 0
3 years ago
This is a question on my partial fractions homework, but no matter what I try I can't figure it out..
Ierofanga [76]
\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{a_1x+a_0}{(x+1)^2}+\dfrac b{x+2}
\implies\dfrac{x^2+x+1}{(x+1)^2(x+2)}=\dfrac{(a_1x+a_0)(x+2)+b(x+1)^2}{(x+1)^2(x+2)}
\implies x^2+x+1=(a_1+b)x^2+(2a_1+a_0+2b)x+(2a_0+b)
\implies\begin{cases}a_1+b=1\\2a_1+a_0+2b=1\\2a_0+b=1\end{cases}\implies a_1=-2,a_0=-1,b=3

So you have

\displaystyle\int_0^2\frac{x^2+x+1}{(x+1)^2(x+2)}\,\mathrm dx=-2\int_0^2\frac x{(x+1)^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}
=\displaystyle-2\int_1^3\dfrac{x-1}{x^2}\,\mathrm dx-\int_0^2\frac{\mathrm dx}{(x+1)^2}+3\int_0^2\frac{\mathrm dx}{x+2}

where in the first integral we substitute x\mapsto x+1.

=\displaystyle-2\int_1^3\left(\frac1x-\frac1{x^2}\right)\,\mathrm dx-\frac1{1+x}\bigg|_{x=0}^{x=2}+3\ln|x+2|\bigg|_{x=0}^{x=2}
=-2\left(\ln|x|+\dfrac1x\right)\bigg|_{x=1}^{x=3}-\dfrac23+3(\ln4-\ln2)
=-2\left(\ln3+\dfrac13-1\right)-\dfrac23+3\ln2
=\dfrac23+\ln\dfrac89
4 0
3 years ago
Roberto is an insurance agent who sells two types of
xz_007 [3.2K]
Answer is D, this is easy.
3 0
3 years ago
Read 2 more answers
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