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Ludmilka [50]
2 years ago
13

What is the area of the kite 10 12 12 18

Mathematics
1 answer:
Brums [2.3K]2 years ago
8 0
P=2A
q so it’s 18
That is the answe
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Two welders worked a total of 46 h on a project. One welder made $34/h, while the other made $39/h. If the gross earnings of the
Ratling [72]

Answer:

25 and 21 hours respectively

Step-by-step explanation:

Let the number of hours worked by each welder be x and y respectively.

They worked a total of 46 hours. This means :

x + y = 46 hours.......(I)

Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:

34x + 39y = 1669........(ii)

We then solve both simultaneously. From I, x = 46 -y

We can substitute this into ii

34(46 -y) + 39y = 1669

1564 -34y + 39y = 1669

5y = 1669 - 1564

5y = 105

y = 105/5 = 21

x = 46 - y

x = 46 - 21 = 25 hours

The numbers of hours worked by the welders are 25 and 21 respectively

4 0
2 years ago
Select the correct answer.
aleksklad [387]

Answer:

B) 454.50

Step-by-step explanation:

-25.50 + 480.00 = 454.50

8 0
3 years ago
Read 2 more answers
Need help with this math problem
elena-14-01-66 [18.8K]

Answer:

Sangayko venchitra ko asalokan gari nimna samuhko ganatmak sankhya Pata lagaunuhos

N(A)

3 0
2 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
2 years ago
Log2(3x-1) = log2 (x+8)
Keith_Richards [23]

Answer:

X= 9/2  

Alternative form

x=4 1/2, x=4.5

Step-by-step explanation:

*= Multiply

1. log (little 10 under) (2)*(3x-1)= log (little 10 under) (2)*(x+8)

2. then divide both side by log (little 10 under (2))

3. 3x-1=x+8

4. move variable to the left side and change its sign

5. 3x-x-1=8

6. then move constant to the right side and change its sign

7. 3x-x=8+1

8. collect like terms

9. 2x=8+1

10. add 8+1

11. 2x=9

12. then divide both sides by 2

13. 2/2 9/2

14. 2/2 cancels out so x=9/2 is the answer

4 0
2 years ago
Read 2 more answers
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