What is the area of the kite 10 12 12 18

Plz help me well mark brainliest if correct.....????.

vichka [17]

The answer is A, 12. :)

4 0

2 years ago

Susan wants to conduct a survey to find how much time the students of her school spent eating in a local cafeteria. Which of the

jekas [21]

Answer:

(D)How many hours during the week do you eat in the cafeteria?

Step-by-step explanation:

This question directly gives her the information she needs. She wants to find out how much time students spend eating in the cafeteria and that is exactly what this question is asking.

7 0

3 years ago

A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean

Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846$

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{9.1 - 8.4}{0.2846}$

$Z = 2.46$

$Z = 2.46$ has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0

2 years ago

Samuel worked at a beach stand over the summer. He worked 6 hours a day 4 days a week. He earned $7.50 per hour how much money d

Nata [24]

Total earning in the summer = $1440
Step-by-step explanation:
Earning per hour for Samuel = $7.50
No. of hours worked in a day = 6
Earning for a day = Earning per hour for Samuel *No. of hours worked in a day
Earning for a day = $7.50 *6 = $45
___________________________________________________
No of days worked in a week by Samuel = 4
Earning for week = Earning for a day *No of days worked in a week by Samuel
Earning for week = $45*4 = $180
_____________________________________________________
No. of weeks worked in summer = 8
Total earning in the summer = Earning for week *No. of weeks worked in summer
Total earning in the summer = $180*8 = $1440 (Answer)

*NOT MY ANSWER SOMEONE ALREADY ANSWERED THIS***

3 0

2 years ago

A number is selected, at random, from the set {1,2,3,4,5,6,7,8}.

Olegator [25]

Applying the formula, you have:

A = the number is prime

B = the number is odd

I assume that with "random" you imply that all numbers can be chosen with the same probability. So, we have

$P(A) = \dfrac{4}{8} = \dfrac{1}{2}$

because 4 out of 8 numbers are prime: 2, 3, 5 and 7.

Similarly, we have

$P(B) = \dfrac{4}{8} = \dfrac{1}{2}$

because 4 out of 8 numbers are odd: 1, 3, 5 and 7.

Finally,

$P(A \land B) = \dfrac{3}{8}$

because 3 out of 8 numbers are prime and odd: 3, 5 and 7.

So, applying the formula, we have

$P(\text{prime } | \text{ odd}) = \dfrac{P(\text{prime and odd})}{P(\text{odd})} = \dfrac{\frac{3}{8}}{\frac{1}{2}} = \dfrac{3}{8}\cdot 2 = \dfrac{3}{4}$

Note:

I think that it is important to have a clear understanding of what's happening from a conceptual point of you: conditional probability simply changes the space you're working with: you are not asking "what is the probability that a random number, taken from 1 to 8, is prime?"

Rather, you are adding a bit of information, because you are asking "what is the probability that a random number, taken from 1 to 8, is prime, knowing that it's odd?"

So, we're not working anymore with the space {1,2,3,4,5,6,7,8}, but rather with {1,3,5,7} (we already know that our number is odd).

Out of these 4 odd numbers, 3 are primes. This is why the probability of picking a prime number among the odd numbers in {1,2,3,4,5,6,7,8} is 3/4: they are literally 3 out of 4.

5 0

3 years ago