3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

1 answer:

7 0

Answer:

i am not 100% sure but i think it would be C

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algol [13]

Answer:

Step-by-step explanation:

Ok ty

4 0

3 years ago

Lerok [7]

Neither or them have a bigger half. Hope it helps!

6 0

3 years ago

masya89 [10]

Q1
r = (2A/θ)^.5 = ((14/(1/8))^.5 = 10.583 ft <--------

q2
θ = 2A/r^2 = 2*3/7^2 = .122 rad <--------

7 0

4 years ago

Ulleksa [173]

16 kids and 1 adult

7 0

3 years ago

Y_Kistochka [10]

Answer: 153

Step-by-step explanation:

When we have a group of N elements, the total number of combinations of K elements ( K ≤ N) is:

$C (N, K) = \frac{N!}{(N-k)!*K!}$

Where N! = N*(N - 1)*(N - 2)*...*2*1

In this case, we have a group of 18 people (then N = 18) and we want to see how many different combinations of 2 we can make (K = 2).

Using the above equation we get:

$C(18, 2) = \frac{18!}{(18 - 2)!*2!} = \frac{18!}{16!*2!} = \frac{18*17}{2} = 9*17 = 153$

There are 153 different ways in which the manager can do this.

5 0

3 years ago