All categories

3 years ago

Please i need help i need 1-12

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

I gotchu. This is pretty simple okay? So when the problem is asking for X and X is inside the triangle, all you have to do is add the other two numbers, which are shown, and subtract it by 180 to get X. For example for problem number 1. You have x that’s inside the triangle, so you add up 47 and 58 which equals to 105 and then take that number and subtract it FROM 180. So the whole equation would be 47+58=105 180-105=75 so X=75. Now for other problems it’s the exact same thing all you have to do is take the other numbers add them up subtract it from 180 and you get X

You might be interested in

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

3) Bar Graphs are used for which type of data?

SCORPION-xisa [38]

Answer:

<u>Bar graphs are used to compare things between different groups or to track changes over time.</u>

However, when trying to measure change over time, bar graphs are best when the changes are larger.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

S is the set of states in the U.S. that border georgia. Alabama∈S

lapo4ka [179]

The elements of the set S are Tennessee, South Carolina, Florida, and Alabama.

A set is a collection of well-defined items or objects.

The items that are found in a set are called the elements of the set.

For example, given a set S, which is the set of states in the U.S. that border Georgia.

The US state Georgia is bordered by Tennessee in the north, South Carolina and the Atlantic Ocean in the east, Florida in the south, and Alabama in the west.

Therefore, the elements of the set S = Tennessee, South Carolina, Florida, and Alabama.

In conclusion, a set consists of well-defined items.

Learn more about sets at: brainly.com/question/2166579

#SPJ1

8 0

2 years ago

When Lin drives a golf ball, it travels a mean distance of 200 yards with a standard deviation of 20 yards, and the distribution

Anettt [7]

Answer:

The percentage of her shots that will travel less than 180 yards is approximately 15.9%

Step-by-step explanation:

First it will be required to find the standard or z-score from the following formula

$z = \frac{x- \mu}{\sigma}$

Where:

z = z or standard score

x = value that is observed = 180 yards

μ = Sample mean = 200 yards

σ = Sample standard deviation yards

Plugging the values, we have;

$z = \frac{180- 200}{20} = -1$

Therefore, the probability that her shots will travel less than 180 is given by the relation;

p( x < 180 yards) = p(z < -1) = 0.15866

Therefore, the percentage of her shots that will travel less than 180 = 0.15866 × 100

= 15.866% ≈ 15.9%.

3 0

3 years ago

What is the median of 7,3,4,7,5,6,5,5,4

kolezko [41]

Your median is 5 because that is the number that is mentioned the most.

A median is a number that i said the most.

And in the pic your median is 7.

Hope this helps you :0

4 0

3 years ago