The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
learn more on sequence here: brainly.com/question/24128922
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Answer:
17; 22; 27; 32
the terms increase by 5 each time
17 + 5 = 22 (the second term)
17 + 5 * 2 = 27 (third term)
So to get to the 52nd term, we have to add 5* 51 = 255 to 17
17 + 255 = 272
Step-by-step explanation:
Answer:
x y
-2 0
0 2
Slope: 1
y-intercept = 2 ( 0, 2 )
Hope this helped!
Have a supercalifragilisticexpialidocious day!
The answer i believe is 4000
