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zaharov [31]
3 years ago
14

What date would be four months prior to January 31st?

Mathematics
1 answer:
Verdich [7]3 years ago
4 0

Answer:

sept 30

Step-by-step explanation:

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Which value of x makes this equation true?<br> -4.9 = -5.6 + x
stiks02 [169]
5.6-4.9=x

.7= x is the answer not .8
3 0
3 years ago
Find the value of x. Then find the missing angle measures of the polygon.
Naily [24]

The sum of the angles equals 540

There are 3 angles that measure (x - 30) and 2 angles that measure (x)

3(x - 30) + 2(x) = 540

3x - 90 + 2x = 540

5x - 90 = 540

5x = 630

x = 126

x - 30   = 126 - 30   = 96

Answer: x = 126,  x-30 = 96

8 0
3 years ago
A small town's phone numbers either begin 373 or 377. How many phone numbers are available?
ser-zykov [4K]

Answer:

  • <u><em>There are 20,000 number available.</em></u>

Explanation:

To determine <em>how many phone numbers are available </em>you need to know how many digits the number contains.

I will assume the same number of digits for other similar questions, i.e. 7.

With 7 digits, the numbers that begin with 373 or 377 can be of the form 373XXXX or 377XXXX.

Where each X can be any digit 0 - 9. Then, there are 10 different options for each X.

Thus, there are 10×10×10×10 = 10,000 different numbers starting with 373 and other 10,000 different numbers starting with 377.

In total, there are 20,000 numbers available.

6 0
3 years ago
5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you
zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

5^{2x-1}+5^{x+1}=250

Separate each exponential:

5^{2x}5^{-1}+5^{x}5^{1}=250

Operating:

\displaystyle \frac{5^{2x}}{5}+5^{x}5=250

Multiplying by 5:

5^{2x}+25\cdot5^x=1250

Rearranging:

5^{2x}+25\cdot5^x-1250=0

Recall that:

5^{2x}=(5^{x})^2

(5^{x})^2+25\cdot5^x-1250=0

Calling

y=5^{x}:

y^2+25y-1250=0

Factoring:

(y-25)(y+50)=0

There are two possible solutions:

y=25

y=-50

Since

y=5^{x}

y cannot be negative, thus:

5^{x}=25=5^2

The solution is:

x = 2

8 0
3 years ago
5                 3                4               7          26       30
Furkat [3]
Please explain more to the question where do the numbers go
4 0
3 years ago
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