BAD=BCD(base angle ,isosceles triangle)
ABD=CBD(given)
BAD+BCD+ABC=180(angle sum of triangle)
36+36+ABC=180
ABC=108
ABC=ABD+CBD
CBD=108/2
=54
therefore
x=54
Here the question is simple.
All because, we only need to find the value of x.
We are given two equations.
5x + 6 = 10 and 10x + 3 =?
So, we will find the the value of x in the first equation, so that we can substitute the value of x in the second one and there we are with the answer.
5x + 6 = 10
For finding the value of x, all we have to do is,
Transpose the number 6 to 10
Therefore. 5x = 10 - 6 ( Take the equal sign as The Magic Bridge on which if anyone crosses it , will change its sign.)
So we have,
5x = 4
So x = 4/5 ( Multiplication will change to division after crossing the equal sign)
( Doubtful? Substitute the value of x and try!)
Now that we got the value of x,
We can just simply substitute the value of x in the second equation.
10x + 3 = ?
x = 4/5
10*4/5 +3 => 5 and 10 get canceled to 2 at the numerator.
By normal multiplication and then addition, we will get,
8 + 3 = 11
Hope this helps!!!! :)
First, let's find the solution.
-2x + 3y = 8
Add 2x to both sides.
3y = 2x + 8
Divide both sides by 3.
y = 2/3x + 8/3
4x + 2/3x + 8/3 = -2
14/3x + 8/3 = -2
Subtract 8/3 from both sides.
14/3x = -14/3
Multiply both sides by 3/14.
x = -1
y = 2/3(-1) + 8/3
y = -2/3 + 8/3
y = 6/3, or 2.
The solution is (-1, 2) which lies in Quadrant II, because its outline is (-, +).
Answer:
The x -coordinate(s) of the point(s) of intersection of these two polynomials are 
The sum of these x -coordinates is 
Step-by-step explanation:
The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).
Thus, 
and we solve for x
Using Zero Factor Theorem: = 0 if and only if = 0 or = 0
The solutions are:
The sum of these x -coordinates is
We can check our work with the graph of the two polynomials.
Answer:
A, D
Step-by-step explanation:
The graph of a proportional relation is a straight line that passes through the origin.
Answer: A, D
