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3 years ago

1. If 5x + 6 = 10, what is the value of 10x + 3?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

Step-by-step explanation:

5x+6=10

-6 -6

5x=4

-------

5 5

x=4/5

10(4/5)+3

8+3=11

Digiron [165]3 years ago

6 0

Here the question is simple.
All because, we only need to find the value of x.
We are given two equations.
5x + 6 = 10 and 10x + 3 =?
So, we will find the the value of x in the first equation, so that we can substitute the value of x in the second one and there we are with the answer.
5x + 6 = 10
For finding the value of x, all we have to do is,
Transpose the number 6 to 10
Therefore. 5x = 10 - 6 ( Take the equal sign as The Magic Bridge on which if anyone crosses it , will change its sign.)
So we have,
5x = 4
So x = 4/5 ( Multiplication will change to division after crossing the equal sign)
( Doubtful? Substitute the value of x and try!)
Now that we got the value of x,
We can just simply substitute the value of x in the second equation.
10x + 3 = ?
x = 4/5
10*4/5 +3 => 5 and 10 get canceled to 2 at the numerator.
By normal multiplication and then addition, we will get,
8 + 3 = 11
Hope this helps!!!! :)

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Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,

xz_007 [3.2K]

The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.

<h3>How to determine the range of a function?</h3>

Given: 12x + 6y = 24

Here x stands for the input and y stands for the output

Replacing y with f(x)

12x + 6f(x) = 24

6f(x) = 24 - 12x

f(x) = (24 - 12x)/6

Domain = {-4, 0, 5}

Put the elements of the domain, one by one, to estimate the range

f(-4) = (24 - 12((-4))/6

= (72)/6 = 12

f(0) = (24 - 12(0)/6

= (24)/6 = 4

f(5) = (24 - 12(5)/6

= (-36)/6 = -6

The range exists {12, 4, -6}

Therefore, the correct answer is option c. {12, 4, -6}.

To learn more about Range, Domain and functions refer to:

brainly.com/question/1942755

#SPJ4

7 0

2 years ago

The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller

Softa [21]

You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think.

4 0

3 years ago

Please answer as soon as possible

OlgaM077 [116]

Answer:

30 cubic units³

Step-by-step explanation:

<u>Given equation:</u>

3 * 2 * 5

<u>Solve for cubic units³</u>

3 * 2 * 5
= 6 * 5
= 30

There are 30 cubic inches³.

Three times Two Times Five
equals Six times Five
equals Thirty.

There are Thirty cubic inches³.

7 0

2 years ago

Read 2 more answers

Consider the following function. f(x) = 7x + 1 x (a) Find the critical numbers of f. (Enter your answers as a comma-separated li

sukhopar [10]

Answer:

a) DNE

b) The function increases for every real value of x.

c) DNE

Step-by-step explanation:

Given a function f(x), the critical points are those in which $f^{\prime}(x) = 0$ , that is, the roots of the first derivative of f(x).

Those critical points let us find the intervals in which the function increases or decreases. If the first derivative in the interval is positive, the function increases in the interval. If it is negative, the function decreases.

If the function increases before a critical point and then, as it passes the critical point, it starts to decrease, we have that the critical point $(x_{c}, f(x_{c}) is a relative maximum.If the function decreases before a critical point and then, as it passes the critical point, it starts to increase, we have that the critical point [tex](x_{c}, f(x_{c}) is a relative minimum.If the function has no critical points, it either always increases or always decreases.In this exercise, we have that:[tex]f(x) = 7x + 1$