Ethers can't form hydrogen bonds with water and so have a low solubility
hope that helps
A body of knowledge and a process of gaining that knowledge
Answer:
= 1.806 × 10^25 molecules.
Explanation:
1 mole of CO2 contains 6.02 × 10^23 molecules
30 moles of CO2 will contain ( 30 × 6.02 × 10^23 )
= 1.806 × 10^25 molecules.
Answer:
The desirable characteristic of Barium suspension are:
<u>Thick layering</u>
<u></u>
Explanation:
First know the meaning of the terms :
1. Rapid flow
2. Thick layering
3. Good mucosal adhesion\
1. Rapid flow : The lower the viscosity of the solution , more is its flow in the solution. For example : Honey has more viscosity so it flows slowly . On the other hand water flow faster.
2. Thick layering : layering is the deposition of one layer of the liquid over other. The deposited layer can be of different substance.
3. Mucosal Adhesion : It is the adhesion(attraction) between two materials ,one of which is mucous.It is attractive force between the drug and the mucus inside the body.
Barium suspension:
<em>It is not a Good mucosal adhesion material because of low solubility in water and lipid .</em>
<em>Only those solution are good in adhesion which have higher solubility in water.</em>
It is widely used as the contrast media for the examination of gastrointestinal because of its <u>Thick Layering Property. It has the consistency of thick glass . At room temperature it is called "warm thick milk"</u>
<u></u>
Answer:
S₁₂
Explanation:
The freezing point depression (ΔTf) is a colligative property that can be calculated using the following expression.
ΔTf = Kf × m
where,
Kf: freezing point depression
m: molality
ΔTf = Kf × m
m = ΔTf / Kf
m = 0.156 °C / (29.8 °C/m)
m = 5.23 × 10⁻³ m
The molality is:
m = moles of solute / kilograms of solvent
moles of solute = m × kilograms of solvent
moles of solute = 5.23 × 10⁻³ mol/kg × 0.5000 kg
moles of solute = 2.62 × 10⁻³ mol
1.00 g corresponds to 2.62 × 10⁻³ moles. The molar mass of Sₙ is:
1.00 g/2.62 × 10⁻³ mol = 382 g/mol
We can calculate n.
n = molar mass of Sₙ / molar mass of S
n = (382 g/mol) / (32.0 g/mol)
n = 11.9 ≈ 12
The molar formula is S₁₂.
