Answer: 0.52 M
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 0.10 M
Volume of
solution = 28 mL = 0.028 L
Putting values in equation 1, we get:
Molarity of
solution = 0.10 M
Volume of
solution = 60 mL = 0.060 L
Putting values in equation 1, we get:
According to stoichiometry :
2 moles of
neutralize 1 mole of
Thus 0.0028 moles of
neutralize=
of
Thus (0.006-0.0014) moles = 0.046 moles of
are left in 88 ml of solution.
Concentration of
will be =![\frac{moles}{\text {Volume in L}}=\frac{0.046}{0.088}=0.52M](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7B%5Ctext%20%7BVolume%20in%20L%7D%7D%3D%5Cfrac%7B0.046%7D%7B0.088%7D%3D0.52M)
Thus the concentration of
in the resulting solution is 0.52 M