Answer:
see explanation
Step-by-step explanation:
A translation using the vector < 3, - 4 > , means
Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so
M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )
N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )
P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )
Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )
Answer:
5/12
Step-by-step explanation:
First you add 1/4+2/3.
You need to change the denominator so that they are equal to each other
If you multiply the 1/4 by 3/3 you will get 3/12 which is equal to 1/4
Then you need to do the same to 2/3. This time you need to multiply it by 4/4 to get the same denominator which will be 2/3*4/4=8/12
Then you add 3/12+8/12=11/12. You don't need to add the denominator.
After this you will need to subtract 11/12 and 1/2. This time you need to only change the denominator for 1/2.
You multiply the denominator and numerator by 6/6 to 1/2 and you will get 6/12 then you are going to subtract 11/12-6/12 and you will get 5/12
These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer:
thw abswer os tywentr yaxel
Step-by-step explanation:
