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amid [387]
3 years ago
14

Chad has 200$ in his bank account, and Jonathan has 300$ in his bank account. Chads account balance increases by 35$ every month

, and his account balance will be B dollars in x months. How much money will be in each boys account when the account balances are equal?
Mathematics
1 answer:
Tcecarenko [31]3 years ago
8 0

Answer:

535

Step-by-step explanation:

Chad has 200$and Jonathan jas 300 and chad bank account get 35

so 200+300=500+35=535

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Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

1.

b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336

Then you can conclude that ∠B is obtuse (because \cos \angle B) and m∠B=110°.

2.

c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871.

Then you can conclude that ∠C is acute (because \cos \angle C>0) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

3 0
3 years ago
Find the Slope Algebraically: x-3y=6
pentagon [3]

Most x to the other side: -3y=-x+6

Divide by -3 to get y=x/3+2


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Need help with this geometry problem hard for me smart people only 100% pls fast due now
34kurt

Answer:

x = 30°

Step-by-step explanation:

We know that the sum of all of the interior angles of a triangle is 180°, therefore, we can write the following equation:

x + 2x + 3x = 180

6x = 180

x = 30°

8 0
4 years ago
Hi can someone please answet this question for me im a bit confused
Jobisdone [24]

Answer:

a)

Step-by-step explanation:

for each point (A, B, C) reduce the 'x-value' by two and reduce the 'y-value' by 7

for example, for point A:

to find A':  (-6, -7) would be (-6-2, -7-7)  which is (-8, -14)

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3 years ago
In a survey of 155155 senior​ executives, 48.448.4​% said that the most common job interview mistake is to have little or no kno
victus00 [196]

Answer:

We conclude that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company.

Step-by-step explanation:

We are given that in a survey of 155 senior​ executives, 48.4% said that the most common job interview mistake is to have little or no knowledge of the company.

We have to use a 0.05 significance level to test the claim that in the population of all senior​ executives, 40% say that the most common job interview mistake is to have little or no knowledge of the company.

Let p = <u><em>population proportion of senior​ executives who said that the most common job interview mistake is to have little or no knowledge of the company</em></u>

So, Null Hypothesis, H_0 : p = 40%     {means that in the population of all senior​ executives, 40​% say that the most common job interview mistake is to have little or no knowledge of the company}

Alternate Hypothesis, H_A : p \neq 40%     {means that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company}

The test statistics that would be used here <u>One-sample z test for proportions</u>;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of senior​ executives who said that the most common job interview mistake is to have little or no knowledge of the company = 48.4%

            n = sample of senior​ executives = 155

So, <u><em>the test statistics</em></u>  =  \frac{0.484-0.40}{\sqrt{\frac{0.484(1-0.484)}{155} } }  

                                       =  2.09

The value of z test statistics is 2.09.

<u>Also, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.09) = 1 - P(Z \leq 2.09)

                       = 1 - 0.9817 = <u>0.0183</u>

<u>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that in the population of all senior​ executives, different from 40​% say that the most common job interview mistake is to have little or no knowledge of the company.

4 0
4 years ago
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