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PilotLPTM [1.2K]
2 years ago
10

PLS HELP ME THIS IS DUE IN A HOUR How many grapefruits did she harvest?

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
6 0

Answer:

2331 grapefruits ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

satela [25.4K]2 years ago
4 0

Answer:

C.) 2331

Step-by-step explanation:

63x37=2331

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Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   \frac{n_1p_1 +n_2p_2}{n_1+n_2}

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

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z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

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z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

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