The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42
Data given;
To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.
Let x represent the cakes
Let y represent the Oreos
The equation is thus;
The equation that shows the number of Cakes and Oreos can by is
3.50x + 2.0y = 42
Learn more about equation here;
Answer:
k = - , k = 2
Step-by-step explanation:
Using the discriminant Δ = b² - 4ac
The condition for equal roots is b² - 4ac = 0
Given
kx² + 2x + k = - kx ( add kx to both sides )
kx² + 2x + kx + k = 0 , that is
kx² + (2 + k)x + k = 0 ← in standard form
with a = k, b = 2 + k and c = k , thus
(2 + k)² - 4k² = 0 ← expand and simplify left side
4 + 4k + k² - 4k² = 0
- 3k² + 4k + 4 = 0 ( multiply through by - 1 )
3k² - 4k - 4 = 0 ← in standard form
(3k + 2)(k - 2) = 0 ← in factored form
Equate each factor to zero and solve for k
3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = -
k - 2 = 0 ⇒ k = 2
Answer:
See explanation below
Step-by-step explanation:
According to the solubility curve attached, let's analyze each sentence to see which one is correct:
<u>"Solubility of NaCl is least affected by temperature"</u>
True. as you can see in the curve, solubility of NaCl remains almost constant at any value of temperature, so in this case, it does not matter the temperature, the NaCl solubility will be the same.
<u>"completely dissolve 60 g of KBr in 100 g of water at 20 °C"</u>
True. As you can see in the graph, solubility of KBr begins at 60 g, so in 20 °C we have something dissolved there. Actually you have like 70 g dissolved there, so, this is true.
<u>"The solubility of KNO3 is the least affected by changes in temperature"</u>
False. The curve for KNO3 is exponencial, so, changes in temperature do actually affect the solubility.
<u>"100 g of KBr will dissolve completely in 100 g of water at 75 °C"</u>
False. According to the curve, 100 g dissolve when we reach more than 100 °C. At 75 °C only about 85 g of KBr is dissolved.
<u>"if you mix 120 g of NaClO3 in 100 g of water at 10 °C, approximately 30 g will not dissolve"</u>
True. In the graph we can clearly see that at 10 °C only about 90 g is being dissolved so, the rest of the mass is still there as mass.
Answer:
4
Step-by-step explanation: