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3 years ago

This circle is centered at the origin, and the length of its radius is 5. What is the equation of the circle?

Mathematics

1 answer:

Artist 52 [7]3 years ago

4 0

Given :-

Circle's centre is at origin.
The radius is 5 u .

To Find :-

The equation of the circle .

Answer :-

As we know that the general equation of circle centred at origin is ,

x² + y² = r²

where r is the radius .Here r =5 , So ,

x² + y² = 5²
x² + y² = 25

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Gamal is buying ham and turkey to make sandwiches for a party. At most, he can spend $50, and he must buy more than 8 pounds of

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What is the expression in radical form? (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

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The radical form of given expression.

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We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

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