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quester [9]
3 years ago
7

What is 1/3 of 24???????

Mathematics
2 answers:
diamong [38]3 years ago
8 0
It’s 7.999 but you could round to 8.
jeka57 [31]3 years ago
5 0

Answer: 8?


Step-by-step explanation:


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FK+M=A-UK solve for K
Elanso [62]
FK+M=A-UK
FK-UK=A-M
(F-U)K=A-M
K=(A-M)/(F-U)
3 0
3 years ago
Need help! Not sure what exactly is going on here!
marishachu [46]

Answer:

idk

Step-by-step explanation:

4 0
4 years ago
What is the value of the expression 3 1/4 - 1 7/8 =
Murljashka [212]
The answer is 45/8
You have make sure that the denominator has the same value!
31/4-17/8=62/8-17/8
=45/8
5 0
3 years ago
Match the equation with its graph. -2/3x - -1/4y=1/3
Volgvan
If the equation is -(2/3) x - (1/4) y = 1/3, it is a straight line, so you can use some special points to identify the graph.

It is easier is you solve the equation for y:

(1/4)y = - 1/3 - (2/3) x

y = (-4/3) - (8/3)x

That is the slope -y-intercept form of the equation.

That means that the slope is -8/3, and the y-intercept is -4/3.

Use this points to identify the graph:

x = 0 => y = - 4/3 ---> (0, - 4/3)

y = 0 => x = - 1/2 -----> (-1/2, 0)

Now you can punt those two points on the graph and draw the line that joins them.

With this procedure you can find the graph of any straight line.
4 0
3 years ago
An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr
Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.  

He must pay an inventory fee of 52 per car and $5 per truck.  

He paid $849 for inventory foes.  

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}

Here we got n > number of cars and trucks, which is practically impossible.  

Hence, for the given conditions, we won’t get a practical solution

8 0
3 years ago
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