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maks197457 [2]
3 years ago
12

Glacier State Bank pays 6% interest, compounded daily. After finding the daily interest rate (to the nearest millionths place) f

or September 5 (92 days in quarter), calculate the interest earned on that date for an account with a balance of $4,000 (to the nearest whole cent).
Mathematics
1 answer:
sveta [45]3 years ago
4 0
6 per cent compounded daily yields
(1 + .(06/365) )^365
= <span> <span> <span> 1.0618313107 </span> </span> </span> -1=
<span> <span> <span> 6.18313107 % annually

Total =  </span></span></span><span>4,000 * (1.0618313107)^(92/365) =
</span><span>$ 4,060.95

Here's a compound interest calculator:
http://www.1728.org/compint.htm

</span>
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Select two ratios that are equivalent to 2:12 A.6:40 B.12:2 C.3:24 D.1:6 E.8:48
Sever21 [200]

Answer:

E

Step-by-step explanation:

2:12 is equivalent to 8:48

7 0
3 years ago
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A thread was folded in half twice. Then, it was cut in a random place. One of the pieces is 8cm, and the longest piece is 18cm.
Elena-2011 [213]

Answer:

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Step-by-step explanation:

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3 years ago
15-<br><br><br> pls help!!!!<br><br><br><br> math<br><br> pls help answer other questions<br> too
ddd [48]

Answer:

A

Step-by-step explanation:

The projection of vector B on unit vector a is

(B•a)a

av(unit vector of v)= 1/√2(-1,1)

u•av= 1/√2 × (-5+7)= √2

(u•av)av= √2 × 1/√2(-1,1)= (-1,1)

3 0
3 years ago
Andre and Elena are reading the same book over the 1 summer. Andre says he has read of the book. Elena ! says she has read 20 mo
ddd [48]

Answer: There are 175 pages in the book.

Step-by-step explanation:

If Elena read 20 more pages than Andre and she read 55 pages, to find out how much Andre read you have to:

55-20= the pages Andre read

55-20=35

Andre read 35 pages.

If Andre read 1/5 of the book, then to find how many pages are in the book, you have to multiply 35 x 5. (Multiply by the reciprocal)

35 x 5= 175

There are 175 pages in the book.

7 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
3 years ago
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