Answer:
No solutions
Step-by-step explanation:
4(2x-3)=2(4x-6)

Same components are present on both sides of equal sign, therefore NO SOLUTIONS are possible.
Answer:
Line of east wedge is: 2x - y = 96
So, Option 1 is correct.
Step-by-step explanation:
The east edge cannot intersect with the west edge means that two lines are parallel.
If the two lines are parallel then they have same slope. We need to find the slopes of given lines and check which line has slope same as slope of west edge.
Slope of west edge.
y = 2x + 5
The standard equation for slope intercept form is:
y = mx+b
where m is the slope. So, m= 2
Now finding line for east edge.
Option 1.
Convert each given equation to standard slope intercept form and find the slope.
2x -y =96
-y = -2x +96
Multiply with -1
y = 2x -96
m = 2
Option 2.
-2x -y = 96
-y = 2x +96
y = -2x-96
m = -2
Option 3
-y-2x =48
-y = 2x +48
y = -2x -48
m = -2
Option 4.
y+2x = 48
y = -2x+48
m = -2
So, only line of Option 1 has slope = 2 which is equal to the slope of west edge.
Line of east wedge is: 2x - y = 96
So, Option 1 is correct.
First, you want to establish your equations.
L=7W-2
P=60
This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.
60=2(7W-2+W)
Now that we only have 1 variable, we can solve.
First, distribute the 2.
60=14W-4+2W
Next, combine like terms.
60=16W-4
Then, add four to both sides.
64=16W
Lastly, divide both sides by 16
W=4
To find the length, we plug in our width.
7W-2
7(4)-2
28-2
L=26
Answer:
148°
Step-by-step explanation:
The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.
arc QN = 2(74°) = 148°
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<em>Comment on the question and answer</em>
Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.
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We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.
Looks like you going to summer school