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Arturiano [62]
3 years ago
12

Help plssssssssssssssssss

Mathematics
1 answer:
Alenkinab [10]3 years ago
4 0

Answer:

the answer is -19.8

Step-by-step explanation:

multiply -9 times 2.2

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Find the standard form of the equation of the ellipse with the given characteristics. Vertices: (4, 0), (4, 14); endpoints of th
saul85 [17]

Answer:

The standard form of the ellipse is \frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1.

Step-by-step explanation:

The major axis of the ellipse is located in the y axis, whereas the minor axis is in the x axis. The center of the ellipse is the midpoint of the line segment between vertices, this is:

(h, k) =\frac{1}{2}\cdot V_{1} (x,y) + \frac{1}{2}\cdot V_{2} (x,y) (1)

If we know that V_{1} (x,y) = (4,0) and V_{2}(x,y) = (4, 14), then the coordinates of the center are, respectively:

(h,k) = \frac{1}{2}\cdot (4, 0) + \frac{1}{2}\cdot (4,14)

(h,k) = (2,0) + (2, 7)

(h, k) = (4, 7)

The length of each semiaxis is, respectively:

a = \sqrt{(1 - 4)^{2}+(7-7)^{2}}

a = 3

b = \sqrt{(4-4)^{2}+(0-7)^{2}}

b = 7

The standard equation of the ellipse is described by the following formula:

\frac{(x-h)^{2}}{a^{2}}+ \frac{(y-k)^{2}}{b^{2}} = 1

Where:

h, k - Coordinates of the center of the ellipse.

a, b - Length of the orthogonal semiaxes.

If we know that h = 4, k = 7, a = 3 and b = 7, then the standard form of the ellipse is:

\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1

4 0
3 years ago
Which one of the following equations represents a circle with its center of origin?
babymother [125]

Answer:

  • A) x² + y² = 5

Step-by-step explanation:

<u>The equation of the circle:</u>

  • (x - h)² + (y - k)² = r²

The center is (h, k)

<u>Wen the center is the origin we have, h = 0, k = 0:</u>

  • x² + y² = r²

The only equation in same format is the first one

3 0
3 years ago
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ozzi
Work shown above! Answer would be A!

5 0
3 years ago
PLEASE HELP TIMED---
LekaFEV [45]

Answer:

6/10

Step-by-step explanation:

i think sorry if incorrect

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