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erastovalidia [21]
3 years ago
6

PLEASE HELP GIVING 20 PTS!!!!!! For circle H, JN = 3, NK = x, LN = 2, and NM = 6. Solve for x. PLEASE HEEELLLLPPPPPPP!!!!!!! I w

ill report if you give a nonesense answer just for points!!!!!!!

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

x=9

Step-by-step explanation:

when two chords intersects each other, then the product of their segments is equal.

JNxNK = LN x NM

3 x x = 2 x 6

x = (3x6)/2 = 18/2 = 9

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\huge\underline{\overline{\mid{\bold{\red{ANSWER}}\mid}}}

Table 3 is showing a proportional relationship between x and y.

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The value of x in table 3 is its square of value of y,

x y

4^{2} = 16

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Tom had 48 coins and 8 friends. How many coins due each friend get?
blagie [28]

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3 years ago
The bacterial strain Acinetobacter has been tested for its adhesion properties, which is believed to follow a normal distributio
pantera1 [17]

Answer:

a) Alternative hypothesis should be one sided. Because Null and Alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b) the hypothesis that mean adhesion is at least 2.66 dyne-cm is true

Step-by-step explanation:

Let μ be the mean adhesion in dyne-cm.

a)

Null and alternative hypotheses are:

H_{0}: μ=2.66 dyne-cm.

H_{a}: μ<2.66 dyne-cm.

b)

First we need to calculate test statistic and then the p-value of it.

test statistic of sample mean can be calculated as follows:

t=\frac{X-M}{\frac{s}{\sqrt{N} } } where

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  • N is the sample size(5)

Sample mean is the average of 2.69, 5.76, 2.67, 1.62 and 4.12 dyne-cm, that is \frac{2.69+5.76+2.67+1.62+4.12}{5} ≈ 3.37

using the numbers we get

t=\frac{3.37-2.66}{\frac{0.7}{\sqrt{5} } } ≈ 2.27

The p-value is ≈ 0.043. Taking significance level as 0.05, we can conlude that sample proportion is significantly higher than 2.66 dyne-cm.

Thus, according to the sample the hypothesis that mean adhesion is at least 2.66  dyne-cm is true

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