3 years ago

Can someone give me the answer to this please

1 answer:

6 0

I believe the correct answer is D. Thank you.

You might be interested in

Komok [63]

check the picture below.

7 0

4 years ago

soldi70 [24.7K]

Per the plot, looks like g(-8) = 1 and g(2) = -4. Then the average rate of change of g over [-8, 2] is

(g(2) - g(-8)) / (2 - (-8)) = (-3 - 1)/10 = -2/5

3 0

3 years ago

luda_lava [24]

Answer:

$9\times 10^7\ \text{grains of sand}$

Step-by-step explanation:

Given that,

A bricklayer needs to order 6300kg of building sand.

1 grain of this sand weighs $7\times 10^{-5}\ kg$ .

We need to find how many grains of sand are there in 6300 kg.

It can be just calculated as follows :

1 grain of sand = $7\times 10^{-5}\ kg$

$6300\ kg=\dfrac{6300}{7\times 10^{-5}}\\\\=9\times 10^7\ \text{grains of sand}$

= 90000000 grans of sand

So, 6300 kg is equal to $9\times 10^7\ \text{grains of sand}$ .

8 0

3 years ago

astra-53 [7]

98.66074 pounds. Estimate that to around 98.67 pounds

3 0

4 years ago

shtirl [24]

Answer: I can’t understand what you wrote

Step-by-step explanation:

7 0

4 years ago

Can someone give me the answer to this please​