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Damm [24]
2 years ago
6

If the area of a rectangle is

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
5 0
(5x+3) is the width, its factors form is (5x+3)(3x-5)
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Help ASAP , 15 points and a brainy.
Step2247 [10]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Shobos mother present age is six times shobos present age. Shobos age five from now will be one third of his mother's present ag
r-ruslan [8.4K]

Answer:

Step-by-step explanation:

From the problem statement, we can setup the following equations:

M = 6S

S + 5 = \frac{1}{3}M

where S is the current age of Shobos and M is the current age of his mother.

Substituting the first equation into the second will allow us to solve for S:

S + 5 = \frac{1}{3}M

S + 5 = \frac{1}{3}(6S)

S + 5 = 2S

S = 5

Substituting this value into the first equation gives us the age of the mother:

M = 6S

M = 6(5)

M = 30

5 0
3 years ago
Read 2 more answers
Which angle has a sine of -1/2 and a cosine of -√3/2
Sergeeva-Olga [200]
\sin x=-\dfrac{1}{2} < 0\\\\\cos x=-\dfrac{\sqrt3}{2} < 0\\\\therefore\ x\in(180^o;\ 270^o)

\text{We know:}\ \tan x=\dfrac{\sin x}{\cos x}\\\\\text{therefore:}\ \tan x=\dfrac{-\frac{1}{2}}{-\frac{\sqrt3}{2}}=\dfrac{1}{2}\cdot\dfrac{2}{\sqrt3}=\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt3}{3}

\tan x=\dfrac{\sqrt3}{3}\Rightarrow x=30^o+180^o\cdot k;\ k\in\mathbb{Z}

x\in(180^o;\ 270^o)\ therefore\ \boxed{x=30^o+180^o=210^o}
8 0
3 years ago
If a linear function has the points ​(0​,1​) and ​(5​,8​) on its​ graph, what is the rate of change of the​ function?
Harrizon [31]
A. 7/4
Rate of change is the same as slope, it is how the line has to go to get from the first to the second point. The slope function is y2-y1 / x2-x1. So we end up with 8-1/5-1 making 7/4
6 0
2 years ago
Can someone help me out please????
ella [17]
She would have 2 2/8 liters of paint left
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3 years ago
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