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Damm [24]
3 years ago
6

If the area of a rectangle is

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
5 0
(5x+3) is the width, its factors form is (5x+3)(3x-5)
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Need help with 1st question !!! Will mark brainlest!!
hjlf
  1. You would calculate this answer with the Pythagorean theorem. The formula is a² + b² = c², which basically means that the sum of two sides squared would equal the side that is missing.
  2. Currently, we are given 6.5 for side 1. The angle measurments we are given is 45º and 90º [the right angle], which means that if we subtract the sum of 45 and 90 from 180 [the total degree amount of every triangle] we can get the missing angle. With the missing angle, we can calculate the length of the second side.
  3. 45º + 90º = 135º. 180º - 135º = 45º.
  4. Now that we have the angles of all three sides [45º, 90º, 45º] we can find the second length of the triangle. The fact that two angles are the same [45º] means that the length is also the same.
  5. Thus proving that M is also 6.5 in length, we can square 6.5 and add both sides to each other once squared.
  6. 6.5² = 42.25.
  7. 42.25 + 42.25 = 84.5.
  8. The square root of 84.5 is 9.19, or 9.2 rounded.

<h2>9.2</h2>
4 0
3 years ago
Guys pls help solve for x
madam [21]

Answer:

x=2

Step-by-step explanation:

x+(2x)^2=18

6 0
3 years ago
Help I don’t know the answer
Amanda [17]
D I have no explanation
4 0
3 years ago
Read 2 more answers
The formula PV = 300 R is used in chemistry. How can this formula be solved for P
german
P = 300/V

Because in order to isolate P, you have to divide V on both sides.
4 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
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