All categories

3 years ago

PLEASE HELP!! ASAP!!! There’s another part

Mathematics

2 answers:

Nostrana [21]3 years ago

6 0

There is no question here

xeze [42]3 years ago

5 0

Answer:

??????????

Step-by-step explanation:

You might be interested in

PLEASE HELP ME WITH BOTH QUESTIONS<br> THANKS!!

vitfil [10]

First one:

cos(A)=AC/AB=3/4.24

cos(B)=BC/AB=3/4.24

Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1

Second one:

To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).

If that's the case, AE is a transversal of parallel lines AB and DE.

And Angle A is congruent to angle E (alternate interior angles).

Therefore sin(A)=sin(E)=0.5

8 0

3 years ago

I need help finding this answer because I am pretty sure it’s C but I don’t know

malfutka [58]

Answer: A) -9

Step-by-step explanation:

If x = -2

Then $3^{x}$ = $3^{-2}$

So, it is -9

5 0

2 years ago

10•1/2+(-6)(-3) Simplified in steps

dangina [55]

Answer:

Step-by-step explanation:

1) (10*0.5)+(-6*-3)

2) (5)+(18) (The 18 isn't negative because of the rule that states "A negative and a negative will become positive"

3) 5+18=23

7 0

3 years ago

Claire runs 10 km in 1 hour. How many kilometers does she run in half an hour? In 2 1/2hours?

Salsk061 [2.6K]

Answer: 5 km and 25 km

7 0

3 years ago

What is an equation of the line that passes through the points (0, -4) and (-4, 6)?

olganol [36]

Answer:

The equation of the line is.

$y=-\frac{5}{2}x-4$

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is.

$\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}$

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

$\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}$

$\frac{x}{-4}=\frac{y+4}{6+4}$

$-\frac{x}{4}=\frac{y+4}{10}$

$-\frac{10x}{4}=y+4$

$-10x=4(y+4)$

$-10x=4y+16$

$4y=-10x-16$

The above equation is divided by 2 both sides.

$2y=-5x-8$

$y=-\frac{5}{2}x-4$

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is $y=-\frac{5}{2}x-4$

8 0

2 years ago