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GenaCL600 [577]
3 years ago
9

Will the fraction 3/7 make each equation true? Choose Yes or No.

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

Yes, No.

Step-by-step explanation:

I hope this helps! Have a great rest of your day!

Arisa [49]3 years ago
7 0

Answer:

1st is yes

2nd is no

Step-by-step explanation:

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Need urgent help in mathematics!! Will mark brainliest!!!!
Nataly [62]

₇P₅ is a permutation. you can find this setting in the statistics menu of your scientific calculator (i think).

If you don't have a scientific calculator, you can use the following formula:

nPr = \frac{n!}{(n - r)!}

₇P₅  = \frac{7!}{(7 - 5)!}

     = \frac{7}{2!}

     = \frac{7 * 6 * 5 * 4 * 3 * 2!}{2!}

     = 7 * 6 * 5 * 4 * 3

    = 2520

Answer: C

3 0
4 years ago
Read 2 more answers
a seed company has a test plot in which it is testing the germination of a hybrid seed, They plant 50 rows of 40 seeds per row.
ziro4ka [17]

Answer:

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

Step-by-step explanation:

x          P(x) x \times P(x)       x^2 \times  P(x)

33         0.02     0.66          21.78

34          0.06     2.04         69.36

35           0.1      3.5        122.5

36           0.2      7.2         259.2

37           0.24     8.88        328.56

38           0.26     9.88        375.44

39            0.1     3.9         152.1

40            0.02     0.8         32

             1        36.86      1360.9

We are supposed to find mean and standard deviation

Mean =\sum x P(x) = 36.86

Standard deviation =\sum x^2P(X)=1360.9

7 0
3 years ago
if you start on the unit circle at (0,-1) and move 360° in the counterclockwise direction, at what angle measure on the unit cir
maks197457 [2]

Answer:

270°

Step-by-step explanation:

(0, -1) is at the 270° angle.  If you do a 360°, you end up back where you started, so the angle is still 270°.

6 0
3 years ago
The following sample of weights was taken from 8 cookies off the assembly line. Construct the 95% confidence interval for the po
Gemiola [76]

Answer:

what are you asking

Step-by-step explanation:

8 0
3 years ago
A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc
aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0
4 years ago
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