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3 years ago

Can a 64 ounce be poured into a 4 ounce cup

Mathematics

2 answers:

PtichkaEL [24]3 years ago

7 0

yes but with 16 4 ounce cups

lions [1.4K]3 years ago

4 0

Yes, but you would have to use 16 4 ounce cups

Becuase 64 divided by 4 is 16

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The average monthly rainfall for 6 months was 28.5 mm. If it had rained 1mm more each month what would the average have been? By

Fynjy0 [20]

Answer:

29.5 mm

Step-by-step explanation:

We are told that the average monthly rainfall for 6 months was 28.5 mm.

Thus, total for the 6 months = 28.5 × 6 = 171 mm

Now, we are told that it rained 1 mm extra each month.

So extra for the six months = 1 × 6 = 6mm

New total for 6 months = 171 + 6 = 177 mm

So, new average for 6 months = 177/6 = 29.5 mm

4 0

3 years ago

Help meeeeeeeeeeeeeeee pleaseee!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

konstantin123 [22]

For the equation F(x) = ax² + bx + c we have:

maximum value if a<0
minimum value if a>0

F(x) = -3x² + 18x + 3 ⇒ a = -3, b = 18

a < 0 ⇒ the function has a maximum value

Quadratic function has the maximum value (or minimum) at vertex of its parabola.

The maximum value is k at x=h where: $h=\dfrac{-b}{2a}$ and k = F(h)

$h=\dfrac{-18}{2\cdot(-3)}=3\\\\F(3)=-3\cdot3^2+18\cdot3+3=-27+54+3=30$

Therefore:

<h3> The function has a maximum value of 30 at x = 3</h3>

3 0

1 year ago

A boiler has five identical relief valves. The probability that any particular valve will open on demand is 0.93. Assume indepen

noname [10]

Answer:

There is a 99.99998% probability that at least one valve opens.

Step-by-step explanation:

For each valve there are only two possible outcomes. Either it opens on demand, or it does not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 5, p = 0.93$

Calculate P(at least one valve opens).

This is $P(X \geq 1)$

Either no valves open, or at least one does. The sum of the probabilities of these events is decimal 1. So:

$P(X = 0) + P(X \geq 1) = 1$

$P(X \geq 1) = 1 - P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.93)^{0}.(0.07)^{5} = 0.0000016807$

Finally

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000016807 = 0.9999983193$

There is a 99.99998% probability that at least one valve opens.

5 0

2 years ago

Read 2 more answers

There are 25 students in a class, and 7 of them will

Elena-2011 [213]

By a Challenge that way It’ll be even

8 0

2 years ago

A school had a girl:boy ratio 5.4.

Ilya [14]

Answer:

164

The 982 part seems wrong. Are you sure it isn't 981?

around 436 if I use 981 instead. 982 would give a decimal and that would be kinda weird for a part human.

Step-by-step explanation:

You can divide the 205 by 5 to simplify the ratio down. 205/5 = 41. Then you can multiply by 4 to find then number of boys.

981

So you can add the 5 and 4 together to 9 and then divide 981 by 9 to get 109. Then you can multiply by 4 to get 436.

Hope this helps!

8 0

2 years ago