1. The average rate of change in a riders height between 1 and 3 seconds -30 ft/s
2. The average rate of change in a riders height between 0 and 5 seconds -24 ft/s
3. Another word for rate of change in this situation is speed
<h3>What is speed? </h3>
Speed is defined as the rate of change of the distance travelled with time. Mathematically, it can be expressed as:
Speed = distance / time
With the above idea, we can obtain the answers to the question given above.
<h3>1. How to determine the rate of change between 1 and 3 seconds</h3>
- Change in height = 30 - 90 = -60 ft
- Change in time = 3 - 1 = 2 s
- Rate of change =?
Rate = Change in height / change in time
Rate = -60 / 2
Rate = -30 ft/s
<h3>2. How to determine the rate of change between 0 and 5 seconds</h3>
- Change in height = 0 - 120 = -120 ft
- Change in time = 5 - 0 = 5 s
- Rate of change =?
Rate = Change in height / change in time
Rate = -120 / 5
Rate = -24 ft/s
<h3>3. what is another word for rate of change?</h3>
From the definition of speed given above, we can say that: another word for rate of change is speed
Learn more about speed:
brainly.com/question/680492
#SPJ1
Answer:
y=0.20p + 0.15n
Step-by-step explanation:
I believe this is correct I am 90% positive that it is right.
Answer:
E=2.8 m-40
Step-by-step explanation:
We konw that 30°E=25°M and 310°E=125°M
so if we want to write an ecuation that linearly relates E with M, we can use the formula of the line that crosses two points:
Y-y1= (y2-y1)/(x2-x1)*(X-x1)
In thts case:
- y1= E1= 30
- y2= E2=310
- x1= M1= 25
- x2=M2=125
so
E-E1= (E2-E1)/(M2-M1)* (M-M1)
E-30 = (310-30)/(125-25)*(M-25)
E-30 =280/100 *(M-25)
E-30 =2.8 M- 280*25/100
E-30 =2.8 M-70
E= 2.8 M-70+30
E=2.8 M-40
Good luck!
Answer:
D.
Step-by-step explanation:
-2 is divided on both sides of the equation, which is the multiplication property of equality. you aren't adding anything/ multiplying anything by 0
