Ask question

Ask question

All categories

mihalych1998 [28]

2 years ago

9

Which of the following functions has an initial value of -1/2 and a rate of change of 0?

1 answer:

Fynjy0 [20]2 years ago

7 0

The function that has the given initial value and rate of change is: D. y = -1/2.

<h3>What is the Initial Value and Rate of Change of a Function?</h3>

A function is given as, y = mx + b, where, m is the rate of change, and b, which is a constant is the initial value.

Given the following:

b = -1/2

m = 0

Plug in the values into y = mx + b

y = 0(x) + (-1/2)

y = -1/2

Therefore, the function is: D. y = -1/2.

Learn more about function on:

brainly.com/question/15602982

#SPJ1

You might be interested in

Simplify the radical expression63x^15y^9/7xy^11

Andre45 [30]

Are the 63x and the y being added or multiplied?

3 0

3 years ago

This scale balanced when 1111plus+tequals=2424. suppose the left side becomes 1919plus+t.how can you change the right side so th

Charra [1.4K]

8 has been added to 11 to make it 19. 8 must be added to 24 to make it 32.

11 +t = 24
11 +8 +t = 24 +8
19 +t = 32

7 0

3 years ago

What expression represents the quotient?

Olenka [21]

Answer:

C

Step-by-step explanation:

Given

$\frac{5x^2+8x+7}{4x}$

Divide each term on the numerator by 4x

= $\frac{5x^2}{4x}$ + $\frac{8x}{4x}$ + $\frac{7}{4x}$

= $\frac{5x}{4}$ + 2 + $\frac{7}{4x}$

8 0

3 years ago

How many solutions y= -2x -4 and y=3x plus 3

Oksi-84 [34.3K]

Answer:

The number of solutions is one

Step-by-step explanation:

Here, we want to get the number of solutions

since the linear equations are not the same, neither do they have the same x-variable, we can have only one solution

6 0

3 years ago

SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

3 years ago