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3 years ago

9

I need to find the sum of this equation please help :)

1 answer:

hoa [83]3 years ago

4 0

Answer:

i think

-17x^2 +3x

.....

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F(x) = 3x + 1; g(x) = 5x - 1<br> Find f/g. (1 point)

zysi [14]

Answer:

$\frac{f}{g} =\frac{3x+1}{5x-1}$

$x\neq \frac{1}{5}$

Step-by-step explanation:

we are given

$f(x)=3x+1$

$g(x)=5x-1$

we have to find f/g

we can write as

$\frac{f}{g} =\frac{f(x)}{g(x)}$

now, we can plug values

and we get

$\frac{f(x)}{g(x)} =\frac{3x+1}{5x-1}$

so,

$\frac{f}{g} =\frac{3x+1}{5x-1}$

we know that denominator can not be zero

so,

$5x-1\neq 0$

now, we can solve for x

$5x-1+1\neq 0+1$

$5x\neq 1$

Divide both sides by 5

and we get

$x\neq \frac{1}{5}$

8 0

3 years ago

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Find the value of:<br> a) 8<br> 9<br> ×<br> −3<br> 4

german

Step-by-step explanation:

89 multiplied by negative 34 gives a negative answer, since positive multiplied by negative is negative hence,

(89) × (-34) = -3026

4 0

2 years ago

A shipping box is shown below how many cubic feet will the shipping box hold

Feliz [49]

Answer

42

Step-by-step

3 0

3 years ago

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Can you help me please

Olenka [21]

Answer:

$log_372 = 3.8928$

Step-by-step explanation:

Given

$log_38 = 1.8928$

Required

Evaluate $log_372$

We have:

$log_372 = log_3(8 *9)$

Apply law of logarithm

$log_372 = log_38 +log_39$

Express 9 as 3^2

$log_372 = log_38 +log_33^2$

Evaluate the exponents

$log_372 = log_38 +2log_33$

$log_33 = 1$ .

So:

$log_372 = log_38 + 2 * 1$

$log_372 = log_38 + 2$

Substitute $log_38 = 1.8928$

$log_372 = 1.8928 + 2$

$log_372 = 3.8928$

5 0

3 years ago

I need the answer please

photoshop1234 [79]

It would first be 0.7 and then 1.1

4 0

3 years ago

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