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meriva
3 years ago
5

1. Solve for x in the following problem.

Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0

Answer:

X=36

Step-by-step explanation:

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2 numbers greater than 19 that are divisible by 2, 3, 6 and 9
Umnica [9.8K]

9*6 = 54 which is also divisible by 2 and 3

another one would be 2*54 = 108

Answer 54 and 108.

8 0
4 years ago
What was the purpose of the coordinate graphing system described by Descartes in his book Discourse on Method?
Lubov Fominskaja [6]
<span>A. to use algebraic methods to solve geometric problems. 
</span>
6 0
4 years ago
Read 2 more answers
This set of ordered pairs shows a relationship between x and y. {(0, -2), (3, 7), (6, 16), (6, 15), (8, 21), (10, 28), (11,31)}
Hunter-Best [27]

Answer:

The closest to the output when the input is approximately 12

Step-by-step explanation:

The given (x, y) coordinates are;

The line of best fit is

x, 0, 3, 6, 6, 8, 10, 11

y, -2, 7, 16, 15, 21, 28, 31

The line of best fit can be obtained from the scatter plot of the given data from where a linear pattern is apparent

A linear line of best fit is a trend line that gives an overall cumulative minimum distance of all the points from the line

The method for constructing a line of best fit includes;

1) The least Squares Method

2) The method of linear regression

3) Construction of line of best fit

a) The area method

b) The dividing method

The least squares equation is given as follows;

\hat y = a + b·x

b = \dfrac{\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{\Sigma (x_i - \overline x)^2 }

From MS Excel, we have;

{\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{ } = 266.8571

{\Sigma (x_i - \overline x)^2 } = 89.42857

∴ b = 266.8571/89.42857 ≈ 2.984

a =\overline y- b \cdot \overline x

From MS Excel, with the given data, we get;

\overline y = 16.57143

\overline x = 6.285714

Therefore;

a = 16.57143 - 2.984 × 6.285714 = -2.185

Therefore, we get the following regression equation;

\hat y = -2.185 + 2.9·x

Where;

x = The input

\hat y = The output

Therefore, when x = 5, we get;

\hat y = -2.185 + 2.9 × 5 = 12.315

Therefore, the closest to the output when the input is 5, y ≈ 12

8 0
3 years ago
for an art project you make a square print with a side length of 8 inches. You make a frame using strip of wood 1 1/4 inch wide.
lord [1]

Given that square print has side length = 8 inches

Given that you make a frame using strip of wood 1 1/4 inch wide. Since frame is on both sides of the square print so new side length after adding the frame =1 \frac{1}{4} + 8 + 1 \frac{1}{4} = 10 + \frac{2}{4} = 10 + \frac{1}{2} = 10.5 inches


Area of the square is given by formula = x^2where x is the side of square

Shape of the frame including print will also be square so

Area of the frame including print = 10.5^2 = 110.25 square inches

Area of the print = 8^2 = 64 square inches


We have to find the area of frame only so we can subtract area of print from the total area


Area of frame = [Area of frame including print] - [Area of print]

Area of frame = 110.25-64 = 46.25


Hence final answer is 46.25 square inches


7 0
3 years ago
You need to wrap a rectangular box for christmas, where the length of the box is four times the width. suppose you have 500 squa
jekas [21]
<span>Width = 4.56 inches Length = 18.26 inches Height = 7.30 inches The box has 6 sides that needs to be covered, so let's create an equation to express the total surface area of the box. A = 2*w*l + 2*w*h + 2*h*l Now since we know that the length is 4 times the width, let's substitute 4w for l in the above equation and simplify. A = 2*w*4w + 2*w*h + 2*h*4w A = 8*w^2 + 2*w*h + 8*h*w A = 8*w^2 + 2*h*w + 8*h*w A = 8*w^2 + 10*h*w A = 2w(4w + 5h) And now since the area has to be 500, let's express h in terms of W. Substitute 500 for A and then solve for h. A = 2w(4w + 5h) 500 = 2w(4w + 5h) 250/w = 4w + 5h 250/w - 4w = 5h (250/w - 4w)/5 = h 50/w - (4/5)w = h So we now can calculate l (length) and h (height) of the box in terms of w. The equation for the volume is: V = lwh Let's substitute 4w for l V = lwh V = 4wwh V = 4hww V = 4hw^2 And substitute (50/w - (4/5)w) for h V = 4hw^2 V = 4(50/w - (4/5)w)w^2 V = (200/w - (16/5)w)w^2 V = 200w - (16/5)w^3 Now since we're looking for the largest possible volume, that should bring to mind "first derivative". We can use the power rule to calculate that easily. V = 200w - (16/5)w^3 V' = 200 - 3(16/5)w^2 V' = 200 - (48/5)w^2 Now the minimum and maximum values of V can only happen where V' equal 0. So let's set it to 0 and calculate w. V' = 200 - (48/5)w^2 0 = 200 - (48/5)w^2 (5/48)*(48/5)w^2 = (5/48)*200 w^2 = 1000/48 = 125/6 w = (5/6)sqrt(30), approximately 4.564354646 Now let's calculate length and height. l = (5/6)sqrt(30) * 4 = 18.25741858 h = 50/w - (4/5)w = 50/((5/6)sqrt(30)) - (4/5)((5/6)sqrt(30)) = 7.302967433 Rounding to 2 decimal places gives w=4.56, l=18.26, h=7.30</span>
8 0
4 years ago
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