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lisov135 [29]
3 years ago
9

Yelena assets that expressions for the exponential functions g(x) = 7 (1.5) ^4x. and h(x) = 7(5.0625) ^ x are equivalent. Show a

nd explain why she is, or is not, correct.
Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

Yelena is correct.

Step-by-step explanation:

Yelena asserts that the two functions:

g(x)=7(1.5)^{4x}\text{ and } h(x)=7(5.0625)^x

Are equivalent.

She is indeed correct. Recall the power of a power property for exponents:

(x^a)^b=x^{ab}

Therefore, we can rewrite function <em>g</em> as:

g(x)=7((1.5)^4)^x

Evaluate the inner expression:

1.5^4=5.0625

Therefore:

g(x)=7(5.0625)^x=h(x)

Hence, Yelena is correct.

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Please solve this question
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The probability that a randomly selected x-value from the distribution will be in the interval:

  • P(35 < x < 45) = 0.6827 and,
  • P(30 < x < 40) = 0.47725

<h3>What is the probability of a normal distribution?</h3>

The probability of a normal distribution can be determined from the symmetrical curve between 1 to 100%.

From the information given:

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To determine the probability that a randomly selected x-value is in the given interval:

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P(35 < x < 45) = P(\dfrac{35-40}{5} < Z < \dfrac{45-40}{5})

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P(35 < x < 45) = P(-1 < Z < 1)

\mathbf{P(35 < x < 45) = P[Z\le 1] -P[Z\le -1]}

Using normal distribution table:

P(35 < x < 45) = 0.8414 - 0.1587

P(35 < x < 45) = 0.6827

P(30 < x < 40) = P(\dfrac{30-40}{5} < Z < \dfrac{40-40}{5})

P(30 < x < 40) = P(\dfrac{-10}{5} < Z < \dfrac{0}{5})

P(30 < x < 40) = P(-2 < Z < 0)

\mathbf{P(30 < x < 40) = P[Z\le0]-P[Z\le -2]}

Using normal distribution table:

P(30 < x < 40) = 0.5 - 0.02275

P(30 < x < 40) = 0.47725

Learn more about the probability of a normal distribution here:

brainly.com/question/4079902

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