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Sav [38]
3 years ago
8

WHAT IS 3x3+5-6+2= iN SHOW YOUR ANSWER

Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0

Answer:

10

Step-by-step explanation:

3 x 3 + 5 - 6 + 2=

PEMDAS states we do multiplication first.

9 + 5 - 6 + 2

Since it's just addition and subtraction, we calculate left to right

14 - 6 + 2

8 + 2

10

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A=4ℼR2 solve for R<br> SHOW ALL STEPSSSSSSSSSSSSS
GuDViN [60]

Given problem;

  A  = 4 π R²

  To solve for R, we have to make it the subject of the expression.

Since

      A  = 4 π R² , follow these steps to find R;

    Multiply both sides by \frac{1}{4\pi }  

 A x \frac{1}{4\pi }  =  \frac{1}{4\pi } x 4 π R²

          \frac{A}{4\pi }   = R²

Then find the square root of both sides

        √R²  = \sqrt{\frac{A}{4\pi } }  

            R  = \sqrt{\frac{A}{4\pi } }

The solution is \sqrt{\frac{A}{4\pi } }

3 0
3 years ago
Write the expanded form of the decimal 0.082¯ using powers of 10
Softa [21]

Answer:

0.082 = 8.2× 10^-2

Step-by-step explanation:

Given the decimal number 0.082, the expanded form using the power of 10 can be gotten by writing the decimal number in standard format(writing as a multiple of 10).

To do that we will shift the decimal point to the front up to the front of digit 8. This shows that the decimal point will be shifted 2times to the front. Since of is shifted 2times to the front, our power of 10 will be -2.

0.082 = 8.2× 10^-2

This gives the required answer.

Note that, the power of 10 is positive when decimals are shifted to the back and negative when shifted to the front(in this case).

3 0
3 years ago
How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your
Rasek [7]

Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).

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