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Elenna [48]
3 years ago
14

Graph y = 2 x + 3 pls help thx <3

Mathematics
2 answers:
quester [9]3 years ago
8 0
Second one I think...
slava [35]3 years ago
5 0
It’s the Second one I think
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A group of people are having a dinner that costs $160, which is to be shared equally. If two more persons join the group and sha
SVEN [57.7K]

Answer:

8 people in the original group.

Step-by-step explanation:

Let x be the number of people who were originally present for the dinner that cost $160.  Their average cost per person would be:

$160/x

If 2 more people join, there are x+2 people.  Ignoring the awkward situation that they apparently did not order any additional food, they agree to share the cost of the dinner.  The average cost is now:

$160/(x+2)

We are told that this new average is now $4 less per person.

$160/(x+2) = ($160/x)  - $4

$160 = (($160/x)  - $4)(x+2)

x = 8 people

6 0
2 years ago
Can you think of another combination of triangle classification that is impossible?
cestrela7 [59]
How about an equilateral right triangle or equiangular right triangle hope this helps
3 0
3 years ago
If f(x) = 4x + 12 is graphed on a coordinate plane, what is the y-intercept of the graph?
Scorpion4ik [409]

Answer:

the y intercept is 12

Step-by-step explanation:

6 0
4 years ago
A rhombus has a base of 8 centimeters and a height of 4.2 centimeters. What is its area? Do not round your answer.
KiRa [710]

Answer:

33.6\ cm^{2}

Step-by-step explanation:

Given that

The Base of a rhombus = 8 centimetres

Height of a rhombus = 4.2 centimetres

Based on the above information, the area of a rhombus is

Area\ of\ rhombus = Base \times height

= 8 \times 4.2

= 33.6\ cm^{2}

By multiplying the base of a rhombus with the height of a rhombus we can get the area of the rhombus and the same is applied & shown in the computation part i.e to be shown above

4 0
3 years ago
Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)
vredina [299]

hello ....

the equation of a plane that is ;  ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4  b= -4  c = -1

then: the equation of a plane that is ;  -4x-4y-z +d =0

but the plane  passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

5 0
4 years ago
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