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Firlakuza [10]
3 years ago
9

Find the equation of the line with slope =8 and passing through (3,21) write your equation in the form y=Mx+b

Mathematics
1 answer:
stiks02 [169]3 years ago
4 0

Answer: y = 8x -3

Step-by-step explanation:

we know the slope already which is 8.

so the equation is: y = 8x + b

subsutite the x and y to get the value of b

21 = 8(3) + b

21 = 24 + b

b = -3

So the equation is: y = 8x -3

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A parabola with no real zeros, a negative leading coefficient, and an odd y-intercept.<br> pls help!
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Answer:

Step-by-step explanation:

A parabolic graph with no real zeros never touches or crosses the x-axis.  

If the leading coefficient is negative, that tells us that the parabola opens down (and, in this case, that the entire graph is below the x-axis, because there are no real zeros.

If the y-intercept is odd, then the constant term, c, in ax^2 + bx + c, must be a negative, odd integer.

Suppose we say that the vertex of a particular parabola that is described by the above is (-2, -1) and that the y-intercept is -3.  (Note:  this is strictly an example.)  Then the vertex equation of this parabola is obtained from the general vertex equation of a parabola,

y = a(x - h)^2 + k.  Here h = -2 and k = -1, and so the particular parabola is

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In general form, this would be y = -a(x^2 + 4x + 4) - 1, or

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3 years ago
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Answer:

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Answer:

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