All categories

3 years ago

Alvin is 6 years younger than elga. the sum of their ages is 92. what is elga's age?

Mathematics

2 answers:

Mice21 [21]3 years ago

5 0

86 cause 92-6=86 when you subtract .

podryga [215]3 years ago

3 0

Answer:

Elga's age be 49 years

Step-by-step explanation:

Let Elga's age be x years

Then, Alvin's age will be (x - 6) years

The sum of their ages is 92

Therefore,

x + (x - 6) = 92

x + x - 6 = 92

2x - 6 = 92

2x = 92 + 6

2x = 98

x = 98 /2

x = 49 years

Hence,

Elga's age be 49 years

You might be interested in

Which statements are true regarding the area of circles & sectors? Check all that apply.

Fynjy0 [20]

Answer:

4pi r

Step-by-step explanation:

7 0

3 years ago

Will give correct answer brainliest

Sidana [21]

I’m pretty sure it’s x=10 because
8x + 50 = 130
So we would subtract 50 from both sides so it would be 8x = 130 - 50 then it would give us 80 so now we have 8x =80, now we will need to divide the 8 on both sides to get x, so 80/8 equals 10

6 0

3 years ago

2x + 3 > 13<br> x= 0<br> is this true?<br> O True<br> O False

omeli [17]

False.

Replace x with 0 and solve:

2(0) + 3 = 0+ 3 = 3

3 is not greater than 13 so the answer is false.

5 0

2 years ago

On a fishing trip, you catch two fish. The weight of the first fish is shown. The second fish weighs at least 0.5 pound more tha

yulyashka [42]

Answer:

w >= 1.7

Step-by-step explanation:

fyi the >= mean less than or equal to

7 0

3 years ago

Find the mean and standard deviation for the set of data.

dem82 [27]

The mean and standard deviation for the set of data will be 16 and 5.87. Then the correct option is A.

<h3>What is a standard deviation?</h3>

It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.

The set of data is given below.

16, 22, 8, 5, 20, 18, 14, 17, 24

The mean of the data set will be

μ = (16 + 22 + 8 + 5 + 20 + 18 + 14 + 17 + 24) / 9

μ = 144 / 9

μ = 16

Then the standard deviation of the data set will be

$\rm \sigma = \sqrt{\dfrac{\Sigma (x_i - \mu)^2}{n}} \\\sigma = \sqrt{\dfrac{(16 - 16)^2 +(22 - 16)^2 + (8-16)^2 + ......+(24-16)^2 }{9}} \\\sigma = \sqrt{\dfrac{310}{9}}\\$

Simplify the expression further, then we have

σ = √34.44

σ = 5.87

The mean and standard deviation for the set of data will be 16 and 5.87.

Then the correct option is A.

More about the standard deviation link is given below.

brainly.com/question/12402189

#SPJ1

3 0

1 year ago