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Zielflug [23.3K]
3 years ago
14

Use your calculator to determine the exponential regression for the following set of data: (HINT: Use the STAT button to enter d

ata into L1 and L2)
1
2.
3
4
5
0
4
8
11
26
52
97
Write your answer in the form y = a(6)
(Round to 3 decimal places, put parentheses around
"b" value)

Mathematics
1 answer:
Alex Ar [27]3 years ago
7 0

Answer:

y = 3.819(1.897)ˣ

Step-by-step explanation:

By using the exponential regression calculator,

Exponential equation from the given data will be,

y = 3.8191(1.8974)ˣ

By rounding all the values up to 3 decimal places,

y = 3.819(1.897)ˣ

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Type an equation for the line
Thepotemich [5.8K]

Answer:

y=-\frac{2}{3}x+1

Step-by-step explanation:

Let the equation of the line given in the graph is,

y = mx + b

Where 'm' is the slope of the line

And 'b' represents the y-intercept

Since slope of a line passing through two points (x_1, y_1) and (x_2,y_2) is modeled by,

m = \frac{y_2-y_1}{x_2-x_1}

If this line passes through (-3, 3) and (3, -1),

m = \frac{3+1}{-3-3}

m = -\frac{4}{6}

   = -\frac{2}{3}

And 'b' = 1

Equation of this line will be,

y=-\frac{2}{3}x+1

4 0
3 years ago
Help please <br> Find the value of x. *
salantis [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
For a binomial probability distribution, it is unusual for the number of successes to be less than μ − 2.5σ or greater than μ +
kirill [66]

Answer:The correct option is a)

The upper limit of successes that would be deemed to be usual is 5, so more than 5 successes would be unusual.

Step-by-step explanation:

The mean of a binomial distribution

μ= np where n=10 and p= 0.2 q= 1-p, q= 1-0.2=0.8

μ= 10×0.2=2

σ=√npq

σ=√10×0.2×0.8=1.26

Is unusual for the number of success to be greater than μ + 2.5σ.

= 2+2.5(1.26)

=5 approximately.

So it is unusual for it to be greater than 0.5. The right option Is a)

7 0
3 years ago
Two circles with the same center are congruent sometimes, always, or never ?
love history [14]
I would go with Never because you would have to have two circles with a different center to be congruent
6 0
4 years ago
Using factoring, which values are the solutions to the quadratic equation 2m2+7m−30=0?
Luden [163]

Answer:

B: m = -6 or m = 5/2

Explanation:

\rightarrow \sf 2m^2 +7m - 30 = 0

<u>breakdown</u>

\rightarrow \sf 2m^2 +12m -5m- 30 = 0

<u>take out common factor</u>

\rightarrow \sf 2m(m +6) -5(m+ 6) = 0

<u>collect into groups</u>

\rightarrow \sf (2m -5)(m+ 6) = 0

<u>set to zero</u>

\rightarrow \sf 2m -5=0, \ m+ 6 = 0

<u>change sides</u>

\rightarrow \sf m=2.5, \ m= -6

8 0
2 years ago
Read 2 more answers
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