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natulia [17]
3 years ago
13

Choose one of the factors of x^3 + 343

Mathematics
1 answer:
djyliett [7]3 years ago
4 0
I've done this test before 

The factor should be x+7 so, none of the above.

Hope I helped! ( Smiles )
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Write y=2(x + 6)(x + 3) in standard form
Volgvan

Answer:

y = 2x² + 18x + 36

Step-by-step explanation:

Given

y = 2(x + 6)(x + 3) ← expand the factors using FOIL

y = 2(x² + 9x + 18) ← distribute parenthesis by 2

  = 2x² + 18x + 36 ← in standard form

6 0
3 years ago
How much time will it take for a bug to travel 5 meters if it is traveling 1 m/s
Sophie [7]

Answer:

5

Step-by-step explanation:

divide the distance by the rate of speed

5/1=5

7 0
3 years ago
Read 2 more answers
A child lies on the ground and looks up at the top of a 17-ft tree nearby. The child is 14 ft away from the tree. What is the an
MakcuM [25]
The value of a is 63.43 degrees
6 0
3 years ago
Read 2 more answers
Given the following sets:
hjlf
<h3>Answer:  10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C =  {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t,   d, h, I, p, t  }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

8 0
3 years ago
2) Evaluate 9 X 364 – 9 X 125 – 9 X 39 without the use of your calculator
Brums [2.3K]

Answer:

<em>9*364 - 9*125 - 9*39 = 1,800</em>

Step-by-step explanation:

<em>Mental Calculation</em>

If we detect known patterns in the calculations, we could easily give their results without the use of calculators.

We are given the expression to evaluate:

9*364 - 9*125 - 9*39

The first thing to note is the 9 is a common factor of all terms, thus we take it out:

9*(364 - 125 - 39)

The negative numbers can be easily added

     125

+     39

------------

     164

Now our expression is much easier:

9*(364 - 164)

The subtraction of 364-164 is 200, thus the result of the operations is:

9*200. We only need to recall 9*2=18 and add two zeros to get 1,800, thus:

9*364 - 9*125 - 9*39 = 1,800

7 0
3 years ago
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