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natulia [17]
3 years ago
13

Choose one of the factors of x^3 + 343

Mathematics
1 answer:
djyliett [7]3 years ago
4 0
I've done this test before 

The factor should be x+7 so, none of the above.

Hope I helped! ( Smiles )
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Insert 2 sets of parentheses to make each sentence true: 2 x 14 – 9 – 17 – 14 = 7 (2 x 14) – 9 – (17 – 14) = 7 2 x (14 – 9) + (–
AlexFokin [52]

Answer:

  2 × (14 – 9) – (17 – 14) = 7

Step-by-step explanation:

Evaluate the choices to see which is true.

(2 x 14) – 9 – (17 – 14) = 7   ⇒  28 -9 -3 ≠ 7

2 x (14 – 9) + (– 17 – 14) = 7   ⇒  2(5) +(-31) ≠ 7

(2 x 14) – (9 – 17) – 14 = 7   ⇒   28 -(-8) -14 ≠ 7

2 x (14 – 9) – (17 – 14) = 7   ⇒   2(5)- 3 = 7 . . . . true

3 0
3 years ago
Mr. Bloop can high jump 5.75 feet. How far short is that of Charles Austin's record of 7 ft 10 in?
a_sh-v [17]

Answer:

5.75 feet is the same as 5 ft 9 inches (because 12 in = 1 ft and 0.75 * 12 = 9 so its 9 in). 7 ft 10 in - 5 ft 9 in = 2 ft 1 in.

6 0
4 years ago
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?
Gwar [14]
First 
4x^{2} + 12x + 3 = 0
determine if this equation were factorable, it's not for this one
so I use quadratic formula, try to search the formula online

x1 =  \frac{-12 +  \sqrt{(12)^{2} - 4*4*3} } {2*4} =  \frac{-12 +  4\sqrt{6} }{8} =  \frac{4(-3 +  \sqrt{6}) }{8} =   \frac{-3 + \sqrt{6}}{2} = - 0.28
x2 = \frac{-12 - \sqrt{(12)^{2} - 4*4*3} } {2*4} = \frac{-12 - 4\sqrt{6} }{8} = \frac{4(-3 - \sqrt{6}) }{8} = \frac{-3 - \sqrt{6}}{2} = - 2.72

<span>x ≈ −2.72 and x ≈ −0.28 is the solution</span>

3 0
4 years ago
A $50 watch was marked up to $60. What is the markup rate? Is it an increase or decrease?
makvit [3.9K]

It's increasing cause it's going higher if it's decreasing it's going lower

3 0
3 years ago
Read 2 more answers
A point P lies on the line with equation y= 4-3X. The point P is a distance √34 from the origin. Find the two possible positions
Oksi-84 [34.3K]

The two possible positions of point P are:

(3, -5) and (0.6, 5.8)

<h3>How to find the two possible positions of point P?</h3>

We know that point P lies on the line:

y = 4 - 3*x

And that the distance between P and the origin is √34, then if the coordinates of point P are (x, y), we have that:

\sqrt{34} = \sqrt{x^2 + y^2}

Now, we can replace "y" in the distance equation by the linear equation, and also remove the square roots:

34 = x^2 + (4 - 3x)^2

Now we can solve the quadratic equation for x:

34 = x^2 + 9x^2 + 16 - 24x\\\\10x^2 - 24x - 18 = 0\\\\

The solutions are:

x = \frac{24 \pm \sqrt{(-24)^2 - 4*10*(-18)} }{2*10} \\\\x = \frac{24 \pm36}{20}

So the two solutions are:

x = (24 + 36)/20 = 3

x = (24 - 36)/20 = -0.6

To get the points, we need to evaluate y on these values:

y = 4 - 3*3 = -5   So we have P = (3, -5)

y = 4 - 3*(-0.6) = 2.2 So we have the point (0.6, 5.8)

There are the two possible positions of point P.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

5 0
2 years ago
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