Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) 
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size 
Mean 
Standard deviation 
Significance level is taken as 
t test statistics

Therefore

Critical point



Therefore
P-value from T distribution table

Conclusion

We Reject the Null Hypothesis 
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
The parent function is f(x) = ∛x
When you change the sign to get g(x) = - ∛x you are reflecting the function over the x-axis (because you are changing the sign of all the images).
When you do g(x + 8) to get h(x) = - ∛ (x + 8) you are shifting the functions 8 units to the left.
Therefore, the answer is the fourth option: reflect the parent function over the x-axis and translate it 8 units to the left.
425 / 50 = 8,5
There you go.
Answer:
calculator
Step-by-step explanation:
Answer:
A x=1.5y i think
Step-by-step explanation: