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antiseptic1488 [7]
3 years ago
9

renee collects baseball and football cards. the number of baseball cards is more than twice the number of football cards . all t

ogether renee has 80 cards. how many of each type of card does renee have ?
Mathematics
1 answer:
Digiron [165]3 years ago
8 0

Answer:

60 baseball and 20 football

Step-by-step explanation:

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jok3333 [9.3K]

9514 1404 393

Answer:

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  7. no; point (2, 5) is not part of the solution in the left graph

Step-by-step explanation:

6. Step 2 should be ...

  -61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n

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7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.

The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.

The point (2, 5) is not a solution to both inequalities.

4 0
3 years ago
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madreJ [45]
<span>-6(-5)+12
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How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

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3 years ago
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Digiron [165]

⇒ common ratio =r=3 and the given sequence is geometric sequence. Where an is the nth term, a is the first term and n is the number of terms. ⇒ 12th term is 708588 .

(May be wrong for some other users, although it's correct for me.)

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