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Ann [662]
3 years ago
11

a bicycle store costs $3600 per month to operate .The store pays an average $80 per bike . The average selling price of each bic

ycle is $120. How many bicycles must the store sell each month to break even?
Mathematics
1 answer:
klemol [59]3 years ago
4 0

3400

Step-by-step explanation:

3600-120=3480,3480+80=3560

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A circle of radius of 4 inches has an arc length of 5.8 inches. Find the measure of the central angle.
kondor19780726 [428]
<h3>SOLUTION : </h3>

The radius of the circle is 4 inch and has an arc length of 5.8 inches . We know that if the central angle is 360° then the arc length is 2\pi r . Similarly when angle is theta ,

\implies Arc = radius \times \theta

Now substitute respective values , from the given data ,

\implies 5.8 inch = 4inch * \theta \\\\\implies 0.14 m = 0.1 * \theta \\\\\implies \boxed{\red{\theta \approx 1.4 \ rad }}

This is our required answer!

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3 years ago
The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n
GarryVolchara [31]

Answer:

(-1,1),(4,-2)

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point (x,y)

Distance between points (x_1,y_1),(x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]

Put (x,y)=(-1,1)

34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34

which is true. So, (-1,1) can be a vertex

Put (x,y)=(4,-2)

34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34

which is true. So, (4,-2) can be a vertex

Put (x,y)=(1,1)

34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22

which is not true. So, (1,1) cannot be a vertex

Put (x,y)=(2,-2)

34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22

which is not true. So, (2,-2) cannot be a vertex

Put (x,y)=(4,-1)

34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30

which is not true. So, (4,-1) cannot be a vertex

Put (x,y)=(-1,4)

34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70

which is not true. So, (-1,4) cannot be a vertex

So, possible points for the vertex are (-1,1),(4,-2)

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3 years ago
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A rectangle has the length that is five times longer than it’s width. If the perimeter of the rectangle is 12 inches, whats the
NemiM [27]
The width would be 1 inch.

Given: L = length = 5W; P = perimeter = 2(L+W) = 12 inches
Required: W = width; 
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Solution:
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Cross check:
              P = 2(L + W)
              12 in = 2(5 in + 1 in)
              12 in = 2(6 in)
              12 in = 12 in
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Iteru [2.4K]
12:26

or 6:13 (simplified)
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3 years ago
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The price of a pair of sunglasses was reduced from $55 to $33. By what percentage was the price of the sunglasses reduced?
Karolina [17]
22% because the doubt know
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