Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
Answer:
Step-by-step explanation:
Answer:
Cos b
Step-by-step explanation:
1/2[sin(a+b)+sin(a-b)]
1/2[sin a cos b +cos a sin b + sin A cos B - cos A sin B]
1/2[2sin a cos b]
sin a cos b
Greater 1 km = 1000 m
so it's greater than 999 m
Solution:
- Perimeter of Rectangle = 346
Let Required length of breadth be x
- Then, Length of Rectangle = 45 + x
Now, We have ;
- Perimeter of Rectangle = 2(l+b)
- Perimeter of Rectangle = 2 ( 45 + x + x
- 346 = 2 ( 45 + 2x )
- 346 = 90 + 4x
- 346 - 90 = 4x
- 256 = 4x
- x = 256 ÷ 4
- x = 64 inches
So, Length of Rectangle = x + 46
Length of Rectangle = 64 + 46
Length of Rectangle = 110 inches
Now, Breadth of Rectangle = 64 inches.
