Answer:
16:12
Step-by-step explanation:
(4+12)=16
16/4 = 4
4x3=12
Another method:
4---------3
16-------x
Cross multiplication
4x=16x3
4x=48
x=12
Answer:
472 3/4
Step-by-step explanation:
Consider the meaning of "one, and one more". That does not mean zero (1-1). Rather, it means two (1+1).
__
Then 3/4 and 472 more is ...
Eric has 472 3/4 buckets filled with sand.
_____
The problem statement here seems to be focused on the filled buckets, rather than the sand stockpile that Eric is working from. The amount in that stockpile is being reduced by the amount that is being used to fill buckets. In short, whether you add or subtract depends on what you're trying to figure.
Answer:
width of one box = 1.25 inches
Step-by-step explanation:
Given data:
12 congruent boxes
Length = 25 inches
height = 2 feet
Volume = 9000 cubic inches
First change the height into inches
1 foot = 12 inches
therefore 2 feet = 24 inches
Volume = Length * width * height
9000 = 25 * width * 24
9000 = 600 * width
width = 9000/600
width = 15 inches
width of one box = width of all boxes / number of boxes
width of one box = 15/12
width of one box = 1.25 inches
Answer:
Step-by-step explanation:
Subset(1,3,5) because it is found in another set.
not subset(2,4,6,7,8,9,10) they are not found in the other set.
Answer:
The answer is 1/3
Step-by-step explanation:
Let the events of getting the no. greater than 4 be (>4).
Then,
<em>n</em><em>(</em><em>s</em><em>)</em><em> </em><em>=</em><em> </em><em>6</em>
<em>n</em><em>(</em><em>></em><em>4</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em>
<em>P</em><em>(</em><em>></em><em>4</em><em>)</em><em> </em><em>=</em><em> </em><em>n</em><em>(</em><em>></em><em>4</em><em>)</em><em>/</em><em>n</em><em>(</em><em>s</em><em>)</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>/</em><em>6</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>3</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
