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Nikolay [14]
3 years ago
14

Randy has $200 dollars in debt. Which of the following shows how much money Randy has in his account?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

Um you need to show us a picture or something because it says which following shows how much Randy has in his account so we need a picture or something.

Sorry!

Step-by-step explanation:

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Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
What is the range of the heights of the girls?
Softa [21]

Answer:

Formula of range is HIGHEST VALUE - LOWEST VALUE....

8 0
1 year ago
Simplify<br>2x + x + x + 2y x 3y x y​
nignag [31]

Answer: 2y^3x4+4x

Step-by-step explanation:

4 0
2 years ago
Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number
Gnoma [55]

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

7 0
3 years ago
What is the first quartile of the set of data shown below?
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The answer would be B 23
7 0
3 years ago
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