Answer: The team won 100 games and losses 28 games
Step-by-step explanation:
Let the number of games won denoted by x and the games lost is denoted by y .
Given : A minor league baseball team plays 128 games in a season.
Team won 16 more than three times as many games as they lost.
Then, the system of equations, we have
We can rewrite equation (2) as 
Now, Eliminate equation (3) from (1), we get
Substitute the value of y in (2), we get
Hence, the team won 100 games and losses 28 games.
Answer:
41
Step-by-step explanation:
Divide 2818 by 70 and it comes out to: 40.2571429 it is not 40 because their is still some left over so there will be 41 ferry's and one of them will not be a full ride!
Answer: the mode is 67.2
Step-by-step explanation:
Given that;
Data Frequency
30 - 34 1
35 - 39 0
40 - 44 3
45 - 49 7
50 - 54 5
55 - 59 10
60 - 64 10
65 - 69 21
70 - 74 12
Mode = ?
we know that mode is the number that has the highest number of appearance of frequency, so in this case, the data group that has the highest frequency (21) is 65 - 69
Lower class boundary of the modal group; L = 65
Frequency of the group before the modal group; Fm-1 = 10
Frequency of the modal group; Fm = 21
Frequency of the group after the modal group; Fm+1 = 12
Group width; G = 4
Now using the formula
Mode = L + [ (Fm - Fm-1) / ( (Fm - Fm-1) + (Fm - Fm+1) ) ] × W
so we substitute
Mode = 65 + [ (21 - 10) / ( (21 - 10) + (21 - 12) ) ] × 4
= 65 + [ 11 / 20] × 4
= 65 + 2.2
= 67.2
Therefore the mode is 67.2
So.... there are a total of 57 toys, which the new and favorites ones are not going to be sold.
The equation would ultimately go into 57 - (15+9+2), which would equal to 31. Ultimately, he sells 31 toys and have 26 left over.
in short, subtracting 57 with the sum of 15+9+2 would equal to 31 toys which means that he sells the 31 toys.
