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lianna [129]
3 years ago
11

Solve for h. h/6 − 1 = −3 h =

Mathematics
2 answers:
densk [106]3 years ago
7 0

Answer:

h =  - 12

Step-by-step explanation:

1) Add 1 to both sides.

\frac{h}{6}  =  - 3 + 1

2) Simplify -3 + 1 to -2.

\frac{h}{6}  =  - 2

3) Multiply both sides by 6.

h =  - 2 \times 6

4) Simplify 2 × 6 to 12.

h =  - 12

<em><u>Therefor</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>h</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-12</u></em><em><u>.</u></em>

snow_lady [41]3 years ago
4 0

Answer:

h = - 12

Step-by-step explanation:

<u>Add </u><u>1</u><u> to both sides of the equation</u>

ℎ/6 − 1 + 1 = − 3 + 1

<u>Simplify</u>

ℎ/6 = − 3 + 1

h/6 = -2

<u>Multiply all terms by the same value to eliminate fraction denominators</u>

6 ⋅ ℎ/6 = 6 ( − 2 )

<u>Cancel multiplied terms that are in the denominator</u>

ℎ = 6 ( − 2 )

<u>Multiply the numbers</u>

ℎ = − 12

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Graph each circle given below right the center and radius of each circle
expeople1 [14]

Answer:

Center: (-3,-2)

Radius: √6

The graph is attached.

Step-by-step explanation:

The equation of the circle has the form:

(x -h)^{2}+(y-k)^{2}=r^{2}

Where (h,k) is the  point of the center of the circle and r is the radius of the circle.

The equation given in the problem is

(x +3)^{2}+(y+2)^{2}=6

 Therefore:

h=-3

k=-2

The center is at (-3,-2)

And the radius is:

r^2=6\\r=\sqrt{6}

Then, you can graph it has you can see in the image attached.

5 0
3 years ago
Read 2 more answers
What is the range of the function?
Goryan [66]

Answer:

1. all real numbers less than or equal to 4 = </= 4.

Answer = YES!

2. all real numbers less than or equal to -3 = </= -3.

Answer = YES!

3. all real numbers greater than or equal to 4 = >/= 4

Answer = YES!

4. all real numbers greater than or equal to -3 = >/= -3

Answer = NO!

Step-by-step explanation:

1. all real numbers less than or equal to 4 = </= 4.

1 + 1 = 2

1 + 2 = 3

2 + 2 = 4

2. all real numbers less than or equal to -3 = </= -3.

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

3. all real numbers greater than or equal to 4

1 + 1 = 2

1 + 2 = 3

1 + 3 = 4

1 + 4 = 5

4. all real numbers greater than or equal to -3

1 - 1 = 0

1 - 2 = -1

1 - 3 = -2

1 - 4 = -3

3 0
3 years ago
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is
marysya [2.9K]

Answer:

(a) 0.14%

(b) 2.28%

(c) 48%

(d) 68%

(e) 34%

(f) 50%

Step-by-step explanation:

Let <em>X</em> be a random variable representing the prices paid for a particular model of HD television.

It is provided that <em>X</em> follows a normal distribution with mean, <em>μ</em> = $1600 and standard deviation, <em>σ</em> = $100.

(a)

Compute the probability of buyers who paid more than $1900 as follows:

P(X>1900)=P(\frac{X-\mu}{\sigma}>\frac{1900-1600}{100})

                   =P(Z>3)\\=1-P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid more than $1900 is 0.14%.

(b)

Compute the probability of buyers who paid less than $1400 as follows:

P(X

                   =P(Z

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid less than $1400 is 2.28%.

(c)

Compute the probability of buyers who paid between $1400 and $1600 as follows:

P(1400

                              =P(-2

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1400 and $1600 is 48%.

(d)

Compute the probability of buyers who paid between $1500 and $1700 as follows:

P(1500

                              =P(-1

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1500 and $1700 is 68%.

(e)

Compute the probability of buyers who paid between $1600 and $1700 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1700 is 34%.

(f)

Compute the probability of buyers who paid between $1600 and $1900 as follows:

P(1600

                              =P(0

*Use a <em>z</em>-table.

Thus, the approximate percentage of buyers who paid between $1600 and $1900 is 50%.

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alexandr1967 [171]

Answer:

Option 2, (-3+8)/2

Step-by-step explanation:

Average: Sum of two numbers/ How many numbers

Sum: -3+8

Amount of Numbers: 2

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What are TWO different ways you know when you are finished dividing?
vfiekz [6]
You know you are finished dividing when you can no longer simply & when you plug it back in to check the answer
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