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Lunna [17]
3 years ago
13

The first term of a geometric sequence is –2 and the common ratio is -1/4 . What are the next three terms of the sequence

Mathematics
2 answers:
rodikova [14]3 years ago
5 0

well -2(-1/4) is .5

so -2, .5,(multiply each by -1/4)

-2, 0.5, -0.125, 0.03125

Mumz [18]3 years ago
3 0

Answer:

\text{The next three terms of G.P is }\frac{1}{2}, \frac{-1}{8}, \frac{1}{32}

Step-by-step explanation:

Given that the first term of a geometric sequence is -2 and the common ratio is -1/4.

we have to find the next three terms of the sequence.

The geometric sequence can be written as

a, ar, ar^2, ar^3, ar^4,...

where a and r are the first term and common ratio.

a=-2, r=\frac{-1}{4}

\text{Second term=}ar=-2\times (\frac{-1}{4})=\frac{1}{2}

\text{Third term=}ar^2=-2\times (\frac{-1}{4})^2=\frac{-1}{8}

\text{Fourth term=}ar^3=-2\times (\frac{-1}{4})^3=\frac{1}{32}

\text{The next three terms of G.P is }\frac{1}{2}, \frac{-1}{8}, \frac{1}{32}

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Tpy6a [65]
Hey.

acc'g to the conditions :

Let Catherine has x
and James has 5 + 3x

Then,

5 + 4x = 41 \\ \\ \implies 4x +5 -5 = 41-5 \\ \\ \implies 4x = 36 \\ \\ \implies x= \dfrac{36}{4} \\ \\ \implies x = 9

Hence

• Catherine has = x = $9,
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Thanks.
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Step-by-step explanation:

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Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,
Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

  • \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }  

In order to use t*, we need to check conditions for using a t-distribution first.

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  • Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
  • Normality: CLT is not met; <u>n < 30</u> for both locations A and B ∴ <u><em>proceed with caution</em></u>!

<u>Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.</u>

<u>Solve for t*:</u>

<u></u>

We need the <u>tail area </u>first.

  • \displaystyle \frac{1-.9}{2}= .05

Next we need the <u>degree of freedom</u>.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

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  • df for B: 18 - 1 = 17
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Use a calculator or a t-table to find the corresponding <u>t-score for df = 5 and tail area = .05</u>.

  • t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

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  • \overline {x}_B = 55
  • s_B=2
  • n_B=18
  • t^{*}=-2.015

Substitute the variables into the formula: \displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}  }.

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Simplify this expression.

  • -16 \ \pm \ -2.015 (\sqrt{5.1453} \ )
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Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

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If we want to <u>interpret</u> the confidence interval of (-20.5707, -11.4293), we can say...

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