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xenn [34]
3 years ago
8

Write the equation of a line that is BOTH PARALLEL and PERPENDICULAR

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

Parallel line: y=-x+27

Perpendicular line: y=x+3

Step-by-step explanation:

y=mx+b, where m is the slope and b is the y-intercept.

Rearrange '2x+4y=16' to fit this format:

2x + 4y = 16

x+y=8

y=-x+8

<u>Parallel line</u>

If two lines are parallel, they have the same slope. So our equation goes from y=mx+b to y=-x+b. We know the line goes through (12,15), so we sub this in to get b:

15=-12+b

b=27

So our equation is y=-x+27

<u>Perpendicular line</u>

If two lines are perpendicular, the slope of one line is the negative inverse of another: eg, if a line had slope=3, the line perpendicular to it would have slope=-1/3. The negative inverse of -1 is 1, so our equation goes from y=mx+b to y=x+b.We know the line goes through (12,15), so we sub this in to get b:

15=12+b

b=3

So our equation is y=x+3

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Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and
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Step-by-step explanation:

We have been given that f be a differentiable function such thatf(3)=15, f(6)=3, f'(3)= -8, and f'(6)= -2. The function g is differentiable and g(x)= f^{-1} (x) for all x.

We know that when one function is inverse of other function, so:

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Plugging x=6 into our equation, we will get:

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