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garik1379 [7]
3 years ago
7

16) through: (1,1), slope = 6

Mathematics
2 answers:
Anton [14]3 years ago
7 0

the correct answer is D

krok68 [10]3 years ago
4 0

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here slope m = 6, thus

y = 6x + c ← is the partial equation

To find c substitute (1, 1) into the partial equation

1 = 6 + c ⇒ c = 1 - 6 = - 5

y = 6x - 5 → D

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zhannawk [14.2K]
The answer is 15 but I don't think that's right so sorry if it's wrong
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3 years ago
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Write y= -3/4 x-6 in standard form using integers.
alexgriva [62]

Answer:

3x + 4y = -24.

Step-by-step explanation:

y= -3/4 x-6

Multiply through by 4:

4y = -3x - 24

3x + 4y = -24.

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nika2105 [10]
The answer is B-40.

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guapka [62]

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5.425

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4 0
3 years ago
Let T:P3→P3 be the linear transformation such that T(â’2x2)=3x2+4x, T(0.5x+3)=â’3x2+3xâ’4, and T(2x2â’1)=â’3x+4. Find T(1), T(
balu736 [363]

It looks like we're told that

T(-2x^2)=3x^2+4x

T\left(\dfrac12x+3\right)=-3x^2+3x-4

T(2x^2-1)=-3x+4

We use the fact that T is linear to find T(1),T(x),T(x^2). First, we notice that

T(-2x^2)+T(2x^2-1)=T(-2x^2+2x^2-1)=T(-1)=-T(1)

We also have

T\left(\dfrac12x+3\right)=T\left(\dfrac12x\right)+T(3)=\dfrac12T(x)+3T(1)

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So once we find T(1), we can determine T(x) and T(x^2). We have

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and using this we find

T(x)=12x^2+12x+16

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Then

T(ax^2+bx+c)=T(ax^2)+T(bx)+T(c)=aT(x^2)+bT(x)+cT(1)

T(ax^2+bx+c)=-\dfrac32\left(a-8b+2c\right)x^2-(2a-12b+c)x+16b-4c

8 0
4 years ago
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